0 + 0 + 5 = 5
0 + 2 + 6 = 8
6 + 7 + 4 = 17
Put the 7 in the appropriate column and carry the 1.
<span>8 + 9 + 7 + </span><span>1(carried)</span><span> = 25</span>
Put the 5 in the appropriate column and carry the 2.
<span>9 + 5 + </span><span>2(carried)</span><span> = 16</span>
Put the 6 in the appropriate column and carry the 1.
<span>2 + </span><span>1(carried)</span><span> = 3</span>
<span>So: 1493 × 245 = 365785</span>
The awser for this problem im preety sure is going to be aswer c
Answer:
3x^2 + x -12 + 15/(x^2+4)
Step-by-step explanation:
Team A) 45 people
Team B) 55 people
A)There are two ways to solve this problem, finding the number of combinations possible for Team B, or the number of combinations possible for Team A.
Team A
It's a given that 20 mathematicians are on team A, which leavs the other 25 people for team A to be chosen from a pool of 80 (100- 20 mathletes)
80-C-25 = 80! / (25!/(80-25)!) =<span>363,413,731,121,503,794,368
</span>or 3.63 x 10^20
Solving using Team B
Same concept, but choosing 55 from a pool of 80 (mathletes excluded)
80-C-25 = 80! / (55!(80-55!) = 363,413,731,121,503,794,368
or 3.63 x 10^20
As you can, we get the same answer for both.
B)
If none of the mathematicians are on team A, then we exclude the 20 and choose 45:
80-C-45 = 80! / (45!(80-45)!) = <span>5,790,061,984,745,3606,481,440
or 5.79 x 10^22
Note that, if you solve from the perspective of Team B (80-C-35), you get the same answer</span>
