I hope you don't find the solution too messy. If there is anything you don't get. Let me know and I will explain it:
Answer:
f(x) = ![\sqrt[3]{x + 6}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%20%2B%206%7D)
+ 1
Step-by-step explanation:
Whenever addition or subtraction occurs within the cube root, it moves horizontally; the opposite is done for the translation, thus if it is addition, which in this case it is, instead of moving the positive direction, the function moves the negative direction.
As opposed to addition or subtraction outside of the cube root, it moves vertically, and in this case, it is translated exactly as stated. Here it states addition, thus the graph moves up in one unit.
The origin of the parent function is at ( 0, 0), in contrast, the origin of the function is at ( -6, 1 )
By using what we know, we can determine that the answer will be f(x) = + 1 since we know that the inside of the cube root should be the opposite of the x value and the outside of the cube root should be the same.
Answer:
b is the answer brainliest please
Answer:
B
Step-by-step explanation:
The problem wants you to PLUG IN x into the correct equation.
1) f(-1) means -1 equals x
f(3) means 3 equals x
For example g(9) means 9 = x and f(3/5) means 3/5 = x and so on.
2) Now that you know x equals two numbers -1 and 3 you have to plug them into a equation.
3) Which equation do you plug it in you may ask? You must plug in -1 into x^2 +3 BECAUSE the condition next to it says you can only plug in numbers to x^2+3 greater than or equal to -1 and less than 2. Therefore, you can plug in -1 to this equation.
-1^2 +3 = <u>4</u>
4) Now you have the number 3. Where do you think we should plug #3 into? Well you can plug it in to the first equation because the condition only allows numbers less then -1. the only option is the last one!!
1, for x >= 2 because 3 is certainly bigger than 2.
This means any number greater than or equal to 2 has to be 1.
SO OUR ANSWER IS 4 AND 1
