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3 years ago

What is the value of 5 in 43.245

1 answer:

6 0

4➡ tens
3 ➡ ones
----------------
2➡tenths
4➡hundredths
5➡ thousandths

Anything behind the decimal point ends with a "ths" ("th" )

So, the value of "5" might be 'thousandths'

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Consider a discrete random variable x with pmf px (1) = c 3 ; px (2) = c 6 ; px (5) = c 3 and 0 otherwise, where c is a positive

PtichkaEL [24]

Looks like the PMF is supposed to be

$\mathbb P(X=x)=\begin{cases}\dfrac c3&\text{for }x\in\{1,5\}\\\\\dfrac c6&\text{for }x=2\\\\0&\text{otherwise}\end{cases}$

which is kinda weird, but it's not entirely clear what you meant...

Anyway, assuming the PMF above, for this to be a valid PMF, we need the probabilities of all events to sum to 1:

$\displaystyle\sum_{x\in\{1,2,5\}}\mathbb P(X=x)=\dfrac c3+\dfrac c6+\dfrac c3=\dfrac{5c}6=1\implies c=\dfrac65$

Next,

$\mathbb P(X>2)=\mathbb P(X=5)=\dfrac c3=\dfrac25$

$\mathbb E(X)=\displaystyle\sum_{x\in\{1,2,5\}}x\,\mathbb P(X=x)=\dfrac c3+\dfrac{2c}6+\dfrac{5c}3=\dfrac{7c}3=\dfrac{14}5$

$\mathbb V(X)=\mathbb E\bigg((X-\mathbb E(X))^2\bigg)=\mathbb E(X^2)-\mathbb E(X)^2$
$\mathbb E(X^2)=\displaystyle\sum_{x\in\{1,2,5\}}x^2\,\mathbb P(X=x)=\dfrac c3+\dfrac{4c}6+\dfrac{25c}3=\dfrac{28c}3=\dfrac{56}5$
$\implies\mathbb V(X)=\dfrac{56}5-\left(\dfrac{14}5\right)^2=\dfrac{84}{25}$

If $Y=X^2+1$ , then $X^2=Y-1\implies X=\sqrt{Y-1}$ , where we take the positive root because we know $X$ can only take on positive values, namely 1, 2, and 5. Correspondingly, we know that $Y$ can take on the values $1^2+1=2$ , $2^2+1=5$ , and $5^2+1=26$ . At these values of $Y$ , we would have the same probability as we did for the respective value of $X$ . That is,

$\mathbb P(Y=y)=\begin{cases}\dfrac c3&\text{for }y=2\\\\\dfrac c6&\text{for }y=5\\\\\dfrac c3&\text{for }y=26\\\\0&\text{otherwise}\end{cases}$

Part (5) is incomplete, so I'll stop here.

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Csqrt%7B272%7D" id="TexFormula1" title="\sqrt{272}" alt="\sqrt{272}" align="absmiddle" class

lozanna [386]

√272 is a real number, and the simplified expression of √272 is 4√17

<h3>How to simplify the expression?</h3>

The expression is given as:

√272

Expand

√272 = √16 * 17

Take the square root of 16

√272 = 4√17

Hence, the simplified expression of √272 is 4√17

Read more about real numbers at:

brainly.com/question/7784687

#SPJ1

7 0

1 year ago

What is the value of z in the equation 3 - 7 = 14? (2 points)<br> 03<br> 4<br> 07<br> 21

Hunter-Best [27]

Answer:

Step-by-step explanation:

3z - 7 = 14

3•7=21

21 - 7 = 14

3 0

3 years ago

You are taking a survey on your experience at Taco Bell. For the first three questions you can

wlad13 [49]

19 out come
9 for the first 3 questions
10 for the last 5 questions

Hope this helps ;)

6 0

2 years ago

C ÷ -3 = 8 I’ve been stuck on this prob for awhile and I need help on it

Otrada [13]

<h2>Answer:</h2><h2>c = -24</h2><h2 /><h2>Hope this helps!!</h2>

8 0

3 years ago