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3 years ago

You flip a coin twice.

Mathematics

1 answer:

Brrunno [24]3 years ago

6 0

Answer:

25%(1/4)

Step-by-step explanation:

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Miya flips a coin and rolls a 6-sided number cube labled 1-6 and records tge outcome. About how many times is she likely to flip

neonofarm [45]

Answer:

4 times

Step-by-step explanation:

Sample space :

6 sided cube = (1, 2, 3, 4, 5, 6)

Coin = (H, T)

Probability = required outcome / Total possible outcomes

Probability of head (H) = P(H) = 1 /2 = 0.5

Probability of 3 = P(3) = 1 /6 = 0.166666

Probability of heads and 3 on a single try = p(H) * p(3) = 0.5 * 0.166666 = 0.083333

Hence, expected number of times this is likely to occur in 48 tries :

0.083333 * 48 = 4

4 0

3 years ago

Please I need help on all of them but it’s okay if you only do a couple but if you do them all I with list you as brainlist I pr

rodikova [14]

Answer:bruh

Step-by-step explanation:

5.00 is the first answer is the biggest number then 4.80 and 1.40 If your doing biggest to smallest but hey f not turn it the other way

4 0

3 years ago

Does anyone want this brainly account?

Anna007 [38]

Send me it I’ll take it

3 0

3 years ago

Average box of crackers is 24.5 ounces with standard deviation of. 8 ounce. What percent of the boxes weigh more than 22.9 ounce

34kurt

Answer:

97.7% of of the boxes weigh more than 22.9 ounces.

15.9% of of the boxes weigh less than 23.7 ounces.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 24.5 ounces

Standard Deviation, σ = 0.8 ounce

We are given that the distribution of boxes weight is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(boxes weigh more than 22.9 ounces)

P(x > 22.9)

$P( x > 22.9) = P( z > \displaystyle\frac{22.9 - 24.5}{0.8}) = P(z > -2)$

$= 1 - P(z \leq -2)$

Calculation the value from standard normal z table, we have,

$P(x > 22.9) = 1 - 0.023 =0.977= 97.7\%$

97.7% of of the boxes weigh more than 22.9 ounces.

b) P(boxes weigh less than 23.7 ounces)

P(x < 23.7)

$P( x < 23.7) = P( z < \displaystyle\frac{23.7 - 24.5}{0.8}) = P(z < -1)$

Calculation the value from standard normal z table, we have,

$P(x < 23.7) =0.159= 15.9\%$

15.9% of of the boxes weigh less than 23.7 ounces.

7 0

3 years ago

last week at the sunshine valley rock festival, joel sold 3 times as many tie-dyed t-shirts as silk-screened shirts. he sold a t

forsale [732]

Answer:

132

Step-by-step explanation:

Let x represent the amount of silk-screened shirts Joel sold:

176 = x + 3x

176/4 = x

44 = x

tie dyed shirts = 3x

= 3 * 44

= 132

5 0

3 years ago

Read 2 more answers