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WARRIOR [948]
3 years ago
15

Find the geometric mean of 15 and 18. Write the exact answer.

Mathematics
2 answers:
NeTakaya3 years ago
4 0
\bf \stackrel{geometric~mean}{\cfrac{15}{x}=\cfrac{x}{18}}\implies 15\cdot 18=x^2\implies 270=x^2~~
\begin{cases}
270=2\cdot 3\cdot 3\cdot 3\cdot 5\\
\qquad 2\cdot 3^2\cdot 3\cdot 5\\
\qquad 30\cdot 3^2
\end{cases}
\\\\\\
\sqrt{270}=x\implies \sqrt{30\cdot 3^2}=x\implies 3\sqrt{30}=x
Pavel [41]3 years ago
4 0
Geometric Mean = 16.431 or the radical form in the picture

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Ivenika [448]
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6 0
3 years ago
Write -5i, 2, and 7 in the simplest polynomial function given the roots
ruslelena [56]

Answer:

x^4-9x^3+39x^2-225x+350

Step-by-step explanation:

The simplest polynomial you can get with that roots are (x-5i)(x+5i)(x-2)(x-7)=x^4-9x^3+39x^2-225x+350

8 0
3 years ago
If -3 1/4 is subtracted from 1 1/3. What will be the result?
Alenkinab [10]

1_1/3 = 4/3

-3_1/4 = -13/4

(4/3) - (-13/4)

(4/3) + (13/4)

We can see that (4/3) + (13/4) leads to a positive answer.

Answer: choice D

4 0
3 years ago
Triangle ABC , m∠A=45° and c = 16, find b.
zmey [24]

Using the cosine function:

\begin{gathered} \cos (\theta)=\frac{_{\text{ }}adjacent}{_{\text{ }}hypotenuse} \\ so\colon \\ \cos (45)=\frac{b}{16} \end{gathered}

Solve for b:

\begin{gathered} b=16\cdot\cos (45) \\ b=8\sqrt[]{2} \end{gathered}

5 0
1 year ago
3 The owners intend to store machinery in the undercover storage. Do you think this is wise? Explain.​
mina [271]

The owners intend to store machinery in the undercover storage is a wise idea as it will not be exposed to too much sunlight or water damage.

<h3>What is seem as a machinery?</h3>

Machinery is known to be any kind of mechanical, electrical, or electronic tool that has been set up to carryout some basic function.

Note that The owners intend to store machinery in the undercover storage is a wise idea as it will not be exposed to too much sunlight or water damage and as such it is advisable only in some cases.

Learn more about machinery from

brainly.com/question/25899244

#SPJ2

7 0
2 years ago
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