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3 years ago

A candy maker buys a bar of chocolate weighing 162 oz. About how many lb does the bar weigh?

Mathematics

2 answers:

Natali [406]3 years ago

7 0

Use dimensional analysis. 1 lb = 16 oz will be the conversion factor. 162 oz x (1 lb/16 oz) = 10.125 lb.

Finger [1]3 years ago

7 0

About 10-ish lbs...

srry if this does not help...

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So the Null hypothesis is rejected in this case

Step-by-step explanation:

The number of celebrities is n = 348

So to solve this we would assume that p is the percentage of people that died on the month preceding their birth month

Generally if there is no death postponement then p will be mathematically evaluated as

$p = \frac{1}{12}$

This implies the probability of date in one month out of the 12 months

Now from the question we can deduce that the hypothesis we are going to be testing is

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This is a hypothesis is stating that a celebrity dies in the month preceding their birth

$Alternative \ Hypothesis H_1 : p < 0.083$

This is a hypothesis is stating that a celebrity does not die in the month preceding their birth

is c is the represent probability for each celebrity which either c = 0 or c = 1

Where c = 0 is that the probability that the celebrity does not die on the month preceding his/ her birth month

and c = 1 is that the probability that the celebrity dies on the month preceding his/ her birth month

Then it implies that

for

n= 1 + 2 + 3 + .... + 348 celebrities

Then the sum of c for each celebrity would be $c_s = 16$

i.e The number of celebrities that died in the month preceding their birth month

We are told that the significance level is $\alpha = 0.05$ , the the z value of $\alpha$ is

$z_{\alpha } = 1.65$

This is obtained from the z-table

Since this test is carried out on the left side of the area under the normal curve then the critical value will be

$z_{\alpha } = - 1.65$

So what this implies is that $H_o$ will be rejected if

$z \le -1.65$

Here z is the test statistics

Now z is mathematically evaluated as follows

$z = \frac{c - np}{\sqrt{np_o(1- p_o)} }$

$z = \frac{16 - (348 *0.083)}{\sqrt{348*0.083 (1- 0.083)} }$

$z =-2.50$

From our calculation we see that the value of z is less than $-1.65$ so the Null hypothesis will be rejected

Hence this tell us that the evidence provided is not enough to conclude that 16 celebrities died a month to their birth month

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