She can give 7.29 ft or 7.3 ft of yarn to her 17 students given that the total measurement of the yarn is 124 ft.

solution:

124ft/17students - the operation used is division, dived 124ft w/c is the measurement of the yarn by 17 students.
7.294117647058824 - simplify the answer by rounding it off, at least one or two decimal points; making it 7.29 ft or 7.3ft

6 0

3 years ago

Totally forgot how to do these?

PtichkaEL [24]

I’m just “answering” this because brainless told me to help out 4 ppl so

5 0

3 years ago

X² - 8x - 33=0<br> complete the square

Andreas93 [3]

<h2>Answer:</h2><h2></h2><h2> $\boxed{x_{1}=-3} \\ \\ \boxed{x_{2}=11}$ </h2>

<h2>Explanation:</h2>

Step 1. Write $x^2 - 8x - 33=0$ in the form $x^2+2ax+a^2=0$

$2a=-8\quad :\quad a=-4$

Step 2. Add and subtract $(-4)^2$ to the left side of the equation

$x^2-8x-33+\left(-4\right)^2-\left(-4\right)^2=0 \\ \\ \\ But: \\ \\ x^2+2ax+a^2=\left(x+a\right)^2 \\ \\ x^2-8x+\left(-4\right)^2=\left(x-4\right)^2$

Step 3. Complete square

$\left(x-4\right)^2-33-\left(-4\right)^2=0 \\ \\ \left(x-4\right)^2-49=0 \\ \\ (x-4)=\pm \sqrt{49} \\ \\ x-4=\pm 7 \\ \\ \boxed{x_{1}=-3} \\ \\ \boxed{x_{2}=11}$

8 0

3 years ago

Each unit in the coordinate plane corresponds to 1 mile. Find the distance from the school to Cherry Street. Round your answer t

GarryVolchara [31]

Answer:

$11.2$

Step-by-step explanation:

We can use the distance formula to solve this problem.

This distance formula states that the distance between two points $(x_1, y_1)$ and $(x_2,y_2)$ is equal to $\sqrt{(\Delta x)^2+(\Delta y)^2}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ .

School is at coordinate point (9,6) and the closest point to school on Cherry St. is (4,-4).

Thus, the distance between school and Cherry Street is $\sqrt{(9-4)^2+(6-(-4))^2}=\sqrt{5^2+10^2}=\sqrt{125}=5\sqrt{5}\approx \boxed{11.2}$

3 0

3 years ago