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djyliett [7]
2 years ago
7

Colleen is cutting pieces of string to tie around party bags for her sister’s

Mathematics
1 answer:
Harrizon [31]2 years ago
7 0

Answer:

875 inches

Step-by-step explanation:

almost 73 feet!

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djyliett [7]
It’s 90 degrees...... 100%
7 0
3 years ago
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The cost of in-state tuition at the University of Florida is $6,380 and is increasing at a rate of 3.1% per year. Write and use
olga_2 [115]

Answer:

loser

Step-by-step explanation:

8 0
3 years ago
PLEASE HELP ME!!!!!!!!!!!!!!!!!!! ASAP :)
Mashcka [7]

Answer:

c) The growth factor per days is 1.08

e) The growth factor per hour is 1.08^{1/24}

Step-by-step explanation:

Given the following data;

P(d) = 10 * 1.08^{d} in thousands.

a. To find the number of insects on day 1;

Day, d = 1

P(d) = 10 * 1.08^{d} ......equation 1

Substituting into the formula, we have;

P(1) = 10 * 1.08^{1}

P(1) = 10 * 1.08

P(1) = 10.08

Therefore, option (a) and (b) are incorrect.

c. To find the growth factor per day;

An exponential function is given by the formula;

y = mg^{x} .....equation 2

Where;

g is the growth factor of a population.

Comparing eqn 2 with eqn 1;

g = 1.08

Therefore, option (c) is correct.

e. To find growth factor per hour;

From equation 1 above;

P(1) = 10 * 1.08^{\frac {1}{2}}

Therefore, option e is correct.

4 0
3 years ago
The question is
PilotLPTM [1.2K]

The unknown side lengths are

Large triangle 10

Medium triangle 2

Small triangle 12/5 or 2.4

Step-by-step explanation:

EFD to ABC is 0.4 or 2/5

EFD to GHI is 0.24 or 6/25

ABC to GHI is 0.6 or 6/10

5 0
3 years ago
. In a study of air-bag effectiveness it was found that in 821 crashes of midsize cars equipped with air bags, 46 of the crashes
jok3333 [9.3K]

Answer:

P(X ≤ 46 | X~B(821, 0.078)) = 0.00885745584

0.00885... < 0.01

The test statistic of 46 is significant

There is sufficient evidence to reject H₀ and accept H₁

Air bags are more effective as protection than safety belts

Step-by-step explanation:

821 crashes

46 hospitalisations where car has air bags

7.8% or 0.078 probability of hospitalisations in cars with automatic safety belts

α = 0.01 or 1% ← level of significance

One-tailed test

We are testing whether hospitalisations in cars with air bags are less likely than in a car with automatic safety belts;

The likelihood of hospitalisation in a car with automatic safety belts, we are told, is 7.8% or 0.078;

So we are testing if hospitalisations in cars with air bags is less than 0.078;

So, firstly:

Let X be the continuous random variable, the number of hospitalisations from a car crash with equipped air bags

X~B(821, 0.078)

Null hypothesis (H₀): p = 0.078

Alternative hypothesis (H₁): p < 0.078

According to the information, we reject H₀ if:

P(X ≤ 46 | X~B(821, 0.078)) < 0.01

To find P(X ≤ 46) or equally P(X < 47), it could be quite long-winded to do manually for this particular scenario;

If you are interested, the manual process involves using the formula for every value of x up to and including 46, i.e. x = 0, x = 1, x = 2, etc. until x = 46, the formula is:

P(X = r) = nCr * p^{r}  * (1 - p)^{n - r}

You can find binomial distribution calculators online, where you input n (i.e. the number of trials or 821 in this case), probability (i.e. 0.078) and the test statistic (i.e. 46), it does it all for you, which gives:

P(X ≤ 46 | X~B(821, 0.078)) = 0.00885745584

Now, we need to consider if the condition for rejecting H₀ is met and recognise that:

0.00885... < 0.01

There is sufficient evidence to reject H₀ and accept H₁.

To explain what this means:

The test statistic of 46 is significant according to the 1% significance level, meaning the likelihood that only 46 hospitalisations are seen in car crashes with air bags in the car as compared to the expected number in car crashes with automatic safety belts is very unlikely, less than 1%, to be simply down to chance;

In other words, there is 99%+ probability that the lower number of hospitalisations in car crashes with air bags is due to some reason, such as air bags being more effective as a protective implement than the safety belts in car crashes.

5 0
3 years ago
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