2x^2y^3z^2 · 4xy^4x^2 Multiply and simplify
1 answer:
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Let the 2 integers be x and y.
Their product is 72, so we write: xy=72. (I)
One of them, say y, is 2 less than 5 times the other. We can write this as the equation:
y=5x-2. (II)
To find one of numbers, say x, we can substitute y with 5x-2, in the first equation:
xy=72,
expanding the left hand side expression we get:
.
Answer: C
Their product is 72, so we write: xy=72. (I)
One of them, say y, is 2 less than 5 times the other. We can write this as the equation:
y=5x-2. (II)
To find one of numbers, say x, we can substitute y with 5x-2, in the first equation:
xy=72,
expanding the left hand side expression we get:
Answer: C