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attashe74 [19]
3 years ago
8

Eleven less than three times a number is 85. Find the number. w=

Mathematics
1 answer:
zubka84 [21]3 years ago
7 0

Answer:

the answer would be 32.

Step-by-step explanation:

add 11 to 85, then divide the number you get (96) by 3.

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Find the value of the trigonometric ratio. Simplify the ratio if possible.
sweet [91]

Step-by-step explanation:

Given that,

BC = 8

Ac = 15

We can find AB using the pythagoas theorem.

AB=\sqrt{AC^2+BC^2}\\\\=\sqrt{15^2+8^2}\\\\AB=17

We know that,

\cos\theta=\dfrac{B}{H}, B is base and H is Hypotenuse

\cosB=\dfrac{8}{17}

Hence, this is the required solution.

3 0
3 years ago
Can anyone give me a geometric sequence will give brainlinest and need sequence of 6
snow_lady [41]

Answer:

3, 6, 9, 12, 15, 18

Step-by-step explanation:

If you count by threes you can make a Geometric Sequence of 6.

Final answer: 3, 6, 9, 12, 15, 18.

3 0
3 years ago
Help me please this test is very important !
Lilit [14]

Answer:

d

Step-by-step explanation:

5>2n+11

5-11>2n

-6>2n

-6/2>n

n<or equal to -3

bubble is filled pointing left

6 0
3 years ago
I need to find the derivative. I’m not very good at this so I am answer asap would be sosososo helpful
Bingel [31]

Answer:

See below.

Step-by-step explanation:

First, notice that this is a composition of functions. For instance, let's let f(x)=\sqrt{x} and g(x)=7x^2+4x+1. Then, the given equation is essentially f(g(x))=\sqrt{7x^2+4x+1}. Thus, we can use the chain rule.

Recall the chain rule: \frac{d}{dx}[f(g(x))]=f'(g(x))\cdot g'(x). So, let's find the derivative of each function:

f(x)=\sqrt{x}=x^\frac{1}{2}

We can use the Power Rule here:

f'(x)=(x^\frac{1}{2})'=\frac{1}{2}(x^{-\frac{1}{2}  })=\frac{1}{2\sqrt{x}}

Now:

g(x)=7x^2+4x+1

Again, use the Power Rule and Sum Rule

g'(x)=(7x^2+4x+1)'=(7x^2)'+(4x)'+(1)'=14x+4

Now, we can put them together:

y'=f'(g(x))\cdot g'(x)=\frac{1}{2\sqrt{g(x)}} \cdot (14x+4)

y'=\frac{14x+4}{2\sqrt{7x^2+4x+1} } =\frac{7x+2}{\sqrt{7x^2+4x+1} }

5 0
3 years ago
If a 50 ft flagpole casts a 95 ft shadow, then how long is the shadow that a 5 ft tall of man casts ?
lesantik [10]

9.5 feet,to find that you must find out how many times longer the shadow of the pole is than the pole, and to do that you must divide 95 by 50, in which you get 1.9. And then to find the length of the shadow the man casts you must multiply his height by 1.9.

8 0
3 years ago
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