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likoan [24]
3 years ago
7

A linear function has the same y-intercept as x + 4y = 20 and its graph contains the

Mathematics
1 answer:
MariettaO [177]3 years ago
8 0

Answer:

(0,5)

Step-by-step explanation:

x + 4y = 20

4y = -x + 20

y = -1/4x + 5

The y - intercept of the line is 5

(0,5)

-Chetan K

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Determine the first five terms I. The sequence that has a recursive rule of f(n) = f(n-1) + 2 for n is greater than or equal to
eimsori [14]

Answer:

Okay let me explain this to you so you understand

So what does f(n) mean?

Well F(n) is saying the function, of n.

Basically we need to make n be any random number.

Well what number do we choose?

In your question, it says n is greater than or equal than 2.

lets start with 2

f(n-1)+2

f(2-1)+2

1+2

3

f(2) is 3

lets do this 4 more times

that leaves us with the first 5 terms

these 5 terms are

3

4

5

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7

7 0
3 years ago
Suppose a card is drawn from a deck of 52 playing cards. what is the probability of drawing a 5 or a king?
BigorU [14]
Since there are 4 fives and 4 kings in a deck of 52 cards, the probability of choosing either a five or a king is 8/52 which simplifies as 2/13.
6 0
3 years ago
A salesperson at a jewelry store earns ​5% commission each week. Last​ week, Jarrod sold $640 worth of jewelry. How much did he
Aleksandr-060686 [28]

Answer:

  $32

Step-by-step explanation:

To find the commission, multiply the rate by the sales:

  commission = 5% × $640 = $32

He made $32 in commission.

__

<em>Additional comment</em>

Many calculators and all spreadsheets can work with percentages directly. If yours can't, or if you can't do this arithmetic mentally, you can use the equivalent decimal or fraction for 5%.

  5% = 5/100 = 0.05 = 1/20

Then 5% × $640 = $640/20 = $64/2 = $32.

3 0
3 years ago
Read 2 more answers
Suppose a movie starts at 5:00 p.m. and Lindsay, a customer who is always late, arrives at the movie theater at a random time be
Arte-miy333 [17]

Answer:

a) We know that the distribution for X is given by: X \sim Unif (a=10, b=45)

The density function for this distirbution is given by:

f(x) = \frac{1}{b-a}= \frac{1}{45-10}= \frac{1}{35} , 10 \leq X \leq 45

So then the height of the uniform density curve would be given by:

h = \frac{1}{35}= 0.029

b) For this case we want to calculate the following probability:

P(X\leq 20)

And we can use the cumulative distribution function given by:

F(X) =\frac{x-a}{b-a}=\frac{x-10}{35} , 10 \leq X \leq 45

And we can calculate the probability like this:

P(X \leq 20) = F(20) = \frac{20-10}{35}=0.286

Step-by-step explanation:

For this case we define our random variable X="Lindsay's late arrival time, in minutes"

Part a

We know that the distribution for X is given by: X \sim Unif (a=10, b=45)

The density function for this distirbution is given by:

f(x) = \frac{1}{b-a}= \frac{1}{45-10}= \frac{1}{35} , 10 \leq X \leq 45

So then the height of the uniform density curve would be given by:

h = \frac{1}{35}= 0.029

Part b

For this case we want to calculate the following probability:

P(X\leq 20)

And we can use the cumulative distribution function given by:

F(X) =\frac{x-a}{b-a}=\frac{x-10}{35} , 10 \leq X \leq 45

And we can calculate the probability like this:

P(X \leq 20) = F(20) = \frac{20-10}{35}=0.286

7 0
4 years ago
What is the domain of the function
IRINA_888 [86]
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\{x|x\ge-5~\land~x\neq0\}
-5\le x
[-5,0)\cup(0,\infty)
6 0
3 years ago
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