Which of the following expressions are equivalent to 6-3?

Use the graph to answer F(-3)=

Virty [35]

Answer:

f(-3) = 1

Step-by-step explanation:

The only point with an x-coordinate of -3 has a y-coordinate of 1. That is the value of the function f(x) for x=-3.

f(-3) = 1

7 0

3 years ago

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At a local store, bananas cost 0.54 per pound , apples cost 2.19 per pound , and oranges cost 1.55 per pound . Aaron bought 3 po

Alex777 [14]

$0.54 x 2.6 =$1.404

$1.28 x 3.1=$3.968

$1.404 rounds to $1.40

$3.968 rounds to $4

$4 = $ 1.40 = $5.40

:)

8 0

3 years ago

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A food safety guideline is that the mercury in fish should be below 1 part per million (ppm). Listed below are the amounts of m

posledela

Answer:

Check the attached document for the solutions, cheers

Step-by-step explanation:

Download docx

7 0

3 years ago

In a G.P the difference between the 1st and 5th term is 150, and the difference between the

liubo4ka [24]

Answer:

Either $\displaystyle \frac{-1522}{\sqrt{41}}$ (approximately $-238$ ) or $\displaystyle \frac{1522}{\sqrt{41}}$ (approximately $238$ .)

Step-by-step explanation:

Let $a$ denote the first term of this geometric series, and let $r$ denote the common ratio of this geometric series.

The first five terms of this series would be:

$a$ ,
$a\cdot r$ ,
$a \cdot r^2$ ,
$a \cdot r^3$ ,
$a \cdot r^4$ .

First equation:

$a\, r^4 - a = 150$ .

Second equation:

$a\, r^3 - a\, r = 48$ .

Rewrite and simplify the first equation.

$\begin{aligned}& a\, r^4 - a \\ &= a\, \left(r^4 - 1\right)\\ &= a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) \end{aligned}$ .

Therefore, the first equation becomes:

$a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) = 150$ ..

Similarly, rewrite and simplify the second equation:

$\begin{aligned}&a\, r^3 - a\, r\\ &= a\, \left( r^3 - r\right) \\ &= a\, r\, \left(r^2 - 1\right) \end{aligned}$ .

Therefore, the second equation becomes:

$a\, r\, \left(r^2 - 1\right) = 48$ .

Take the quotient between these two equations:

$\begin{aligned}\frac{a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right)}{a\cdot r\, \left(r^2 - 1\right)} = \frac{150}{48}\end{aligned}$ .

Simplify and solve for $r$ :

$\displaystyle \frac{r^2+ 1}{r} = \frac{25}{8}$ .

$8\, r^2 - 25\, r + 8 = 0$ .

Either $\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}$ or $\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}$ .

Assume that $\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}$ . Substitute back to either of the two original equations to show that $\displaystyle a = -\frac{497\, \sqrt{41}}{41} - 75$ .

Calculate the sum of the first five terms:

$\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= -\frac{1522\sqrt{41}}{41} \approx -238\end{aligned}$ .

Similarly, assume that $\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}$ . Substitute back to either of the two original equations to show that $\displaystyle a = \frac{497\, \sqrt{41}}{41} - 75$ .

Calculate the sum of the first five terms:

$\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= \frac{1522\sqrt{41}}{41} \approx 238\end{aligned}$ .

4 0

3 years ago

Jane works as a tutor for $14 an hour and as a waitress for $11 an hour. This month, she worked a combined total of 93 hours at

daser333 [38]

Answer:

3t + 1,023

Step-by-step explanation:

The computation is shown below:

As a tutor it is $14 per hour

As a waitress it is $11 per hour

Total number of hours worked is 93

Now let us assume the number of hours worked as a tutor is t

So as a waiter is 93 - t

Now the equation is

= $14(t) + $11(93 - t)

= 14t + 1,023 - 11t

= 3t + 1,023

3 0

3 years ago