Answer:
M=0
Step-by-step explanation:
i did math
There are 10 balls in the Urn Total.
Red: 6
Green: 4
Question One: The probability that five red and two green is selected is likely. (as that is over half for both)
Question Two: Impossible. There is only 6 red balls, and 7 are taken from the urn. Thus it would at most be possible for 6 red and 1 green.
Question Three: At least four is likely, as there is more red then green in the Urn.
Hope I helped!
(Mark Brainliest if you can please!)
THIS IS THE CORRECT ANSWER I GOT WHEN SOLVING ON MY IPHONE
n² - 4n = 0
n(n) - n(4) = 0
n(n - 4) = 0
n = 0 or n - 4 = 0
+ 4 + 4
n = 4
Solution Set: {0, 4}
