Determine the quadrant adding or subtracting periods -10pi/3+2pi=-4pi/3+2pi=2pi/3
which is the second quadrant because
first quadrant is between 0 and pi/2
second quadrant is between pi/2 and pi
third quadrant is between pi and 3pi/2
fourth is between 3pi/2 and 2pi
now we find the terminal angle since it is the second quadrant we use theta'=pi-theta=pi-2pi/3=pi/3
sin(pi/3)=sqrt(3)/2 sin is positive in the second quadrant
cos(pi/3)=-0.5 cos is negative in the second quadrant
tan(pi/3)=sin(pi/3)/cos(pi/3)=-sqrt(3) tan is negative in the second quadrant
Answer: x = 20.2
Step-by-step explanation:
Hi how are you hope all is well
Answer:
2.92
Step-by-step explanation:
![V=\frac{4}{3}\pi r^3 \\ \\ 105=\frac{4}{3}\pi r^3 \\ \\ r^3=\frac{105}{\frac{4}{3}\pi} \\ \\ r=\sqrt[3]{\frac{105}{\frac{4}{3}\pi}} \\ \\ r \approx 2.92](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%20r%5E3%20%5C%5C%20%5C%5C%20105%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%20r%5E3%20%5C%5C%20%5C%5C%20r%5E3%3D%5Cfrac%7B105%7D%7B%5Cfrac%7B4%7D%7B3%7D%5Cpi%7D%20%5C%5C%20%5C%5C%20r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B105%7D%7B%5Cfrac%7B4%7D%7B3%7D%5Cpi%7D%7D%20%20%5C%5C%20%5C%5C%20r%20%5Capprox%202.92)
