Simplify 200xyz3 .
1 answer:
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Answer:
0.2941 = 29.41% probability that it was manufactured during the first shift.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Defective
Event B: Manufactured during the first shift.
Probability of a defective item:
1% of 50%(first shift)
2% of 30%(second shift)
3% of 20%(third shift).
So
Probability of a defective item being produced on the first shift:
1% of 50%. So
What is the probability that it was manufactured during the first shift?
0.2941 = 29.41% probability that it was manufactured during the first shift.
Answer: 0.5507
Step-by-step explanation:
Given : The waiting time, in hours, between successive speeders spotted by a radar unit is a continuous random variable X with a cumulative distribution function
Since , the waiting time is in hours , then we can write 12 minutes as hour i.e.0.2 hour.
Now, the probability of waiting fewer than 12 minutes between successive speeders is given by :-
Hence, the required probability = 0.5507