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Andreas93 [3]
3 years ago
5

Please help i will mark you brainliest !

Mathematics
1 answer:
pav-90 [236]3 years ago
3 0

Answer:

  1. Take two points
  2. y=-2x-3
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****ASAP*****<br> can someone pls help me with this? and can you describe it please?
Studentka2010 [4]

Add 165 to 245. That is a total of 410kWh.

245kWh is more than 50% of 410kWh.

So, according to the plan, you will pay NightTimer rate for kWh at night and DayTimer rate during the day.

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(165*0.05281)+(245*0.05456)\\8.71365+13.3674=22.08085

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4 years ago
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A single card is drawn from a standard 52-card deck. Let D be the event that the card drawn is a black card and let F be the eve
tester [92]

Answer:

The indicated probability of P(D \cup F')=\frac{25}{26}

Step-by-step explanation:

Probability of an event E to be;

P(E) = \frac{Number of events within E}{Total number of possible outcomes}

As per the given condition:

Total number of possible outcomes =  52 cards.

Let the event be D and F as follows;

D : Drawn card is a black card

F : Drawn card is a 10 card.    

Then,

From the given condition:

P(D) = \frac{26}{52}   [Out of 52 cards, 26 were black] ,

P(F) = \frac{4}{52}    [Out of 52 cards, there are four  10 cards]

For any two events A and B we always have;

P(A \cup B) = P(A)+P(B)-P(A \cap B)

Now, we have to find the indicated probability:

P(D \cup F')=P(D)+P(F')-P(D \cap F')               ......[1]

First find the P(F');

P(F') =1-P(F) = 1-\frac{4}{52} =\frac{52-4}{52} =\frac{48}{52}

Also, to find P(D \cap F').

We use the formula :

For any event A and B independent variable.

P(A \cap B) =P(A) \cdot P(B)

then;

P(D \cap F') =P(D) \cdot P(F') = \frac{26}{52} \cdot \frac{48}{52} =\frac{24}{52}

Now, substitute these in [1];

P(D \cup F')=\frac{26}{52} +\frac{48}{52} -\frac{24}{52}=\frac{26+48-24}{52} =\frac{50}{52} = \frac{25}{26}

Therefore, the probability of P(D \cup F')=\frac{25}{26}



3 0
3 years ago
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