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Describe how to find the scale factor if an antenna is 60 feet long and a scale drawing shows the length as 1 foot long. Please

bekas [8.4K]

The actual is 60 feet long, the drawing is only 1 foot long. So the scale factor must be 1/60. You know that the scale factor has to be less than one in this case because you're going from a bigger measurement to a smaller measurement(60 to 1).

3 0

3 years ago

What is the geometric definition of a circle

Mazyrski [523]

Answer:

See explanation

Step-by-step explanation:

A circle is a figure where all of the points on its graph are equidistant from a single, central point. You can define a circle in a plane with the formula (x-h)^2+(y-k)^2=r^2, where h represents the x coordinate of the center, k represents the y coordinate, and r represents the radius. Hope this helps, and feel free to ask for more clarification!

3 0

3 years ago

Read 2 more answers

Which pair of angles in the correct category to indicate whether the pair of angles is pair of vertical angles, a pair of line a

densk [106]

We’re is the picture

7 0

3 years ago

This problem please

miskamm [114]

surface areas:

1. 94 ft

2. 96 cm

volumes:

1. 60 ft

2. 42 cm

3 0

3 years ago

In early 2012, the Pew Internet and American Life Project asked a random sample of U.S. adults, "Do you ever ... use Twitter or

8090 [49]

Answer:

The confidence interval for the mean is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

And the confidence interval is given by:

(0.123, 0.177)

And for this case the interval contains the value 0.16, so then we can conclude at 5% of significance that the true proportion is not different from 0.16

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The confidence interval for the mean is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

And the confidence interval is given by:

(0.123, 0.177)

And for this case the interval contains the value 0.16, so then we can conclude at 5% of significance that the true proportion is not different from 0.16

3 0

3 years ago