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Wewaii [24]
3 years ago
13

ASAP PLEASE HELP!!!!

Mathematics
2 answers:
zzz [600]3 years ago
8 0

Answer:

It will take Josie 80 minutes to run 10 miles.

Step-by-step explanation:

We can set up a proportion between the number of minutes she runs to the number of miles she runs. From what we know in the equation, we know that it takes her 24 minutes to run 3 miles, and it takes x minutes to run 10 miles. We can represent this in a proportion!

We know that the ratio of 24:3 will be the same for any number of miles, so we can say

\frac{24}{3} =\frac{x}{10\\}

We can solve this by first simplifying the left hand side then isolation x by multiple both sides of the equation by 10.

24/3 = 8

8 = \frac{x}{10}

80 = x

It will take Josie 80 minutes to run 10 miles.

Elenna [48]3 years ago
5 0
90 minutes the ratio is. 90:10
90 to 10
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G/3 + 11 = 25 please help​
pochemuha

Answer: g = 42

Step-by-step explanation:

g/3 + 11 = 25

First, subtract 11 to both sides

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Then, multiply 3 to both sides to get rid of the fraction

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8 0
3 years ago
The top and bottom margins of a poster 66 cm each, and the side margins are 44 cm each. If the area of the printed material on t
jasenka [17]

Answer:

  • width: 24 cm
  • height: 36 cm

Step-by-step explanation:

When margins are involved, the smallest area will be the one that has its dimensions in the same proportion as the margins. If x is the "multiplier", the dimensions of the printed area are ...

  (4x)(6x) = 384 cm^2

  x^2 = 16 cm^2 . . . . . divide by 24

  x = 4 cm

The printed area is 4x by 6x, so is 16 cm by 24 cm. With the margins added, the smallest poster will be ...

  24 cm by 36 cm

_____

<em>Comment on margins</em>

It should be obvious that if both side margins are 4 cm, then the width of the poster is 8 cm more than the printed width. Similarly, the 6 cm top and bottom margins make the height of the poster 12 cm more than the height of the printed area.

_____

<em>Alternate solution</em>

Let w represent the width of the printed area. Then the printed height is 384/w, and the total poster area is ...

  A = (w+8)(384/w +12) = 384 +12w +3072/w +96

Differentiating with respect to w gives ...

  A' = 12 -3072/w^2

Setting this to zero and solving for w gives ...

  w = √(3072/12) = 16 . . . . matches above solution.

__

<em>Generic solution</em>

If we let s and t represent the side and top margins, and we use "a" for the printed area, then the above equation becomes the symbolic equation ...

  A = (w +s)(a/w +t)

  A' = t - sa/w^2

For A' = 0, ...

  w = √(sa/t)

and the height is ...

  a/w = a/√(sa/t) = √(ta/s)

Then the ratio of width to height is ...

  w/(a/w) = w^2/a = (sa/t)/a

  width/height = s/t . . . . . . the premise we started with, above

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the hieght will be 58.10m

Step-by-step explanation:

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