Answer:
whats your question im confused
Step-by-step explanation:
<span>N(t) = 16t ; Distance north of spot at time t for the liner.
W(t) = 14(t-1); Distance west of spot at time t for the tanker.
d(t) = sqrt(N(t)^2 + W(t)^2) ; Distance between both ships at time t.
Let's create a function to express the distance north of the spot that the luxury liner is at time t. We will use the value t as representing "the number of hours since 2 p.m." Since the liner was there at exactly 2 p.m. and is traveling 16 kph, the function is
N(t) = 16t
Now let's create the same function for how far west the tanker is from the spot. Since the tanker was there at 3 p.m. (t = 1 by the definition above), the function is slightly more complicated, and is
W(t) = 14(t-1)
The distance between the 2 ships is easy. Just use the pythagorean theorem. So
d(t) = sqrt(N(t)^2 + W(t)^2)
If you want the function for d() to be expanded, just substitute the other functions, so
d(t) = sqrt((16t)^2 + (14(t-1))^2)
d(t) = sqrt(256t^2 + (14t-14)^2)
d(t) = sqrt(256t^2 + (196t^2 - 392t + 196) )
d(t) = sqrt(452t^2 - 392t + 196)</span>
Answer:
<h2>m = k / 1/2 over v</h2>
Step-by-step explanation:
1/2mv = k
rearranged can be:
m = k / 1/2 over v
Answer:
14
Step-by-step explanation:
You can solve using PEMDAS:
Parentheses
Exponents
Multiplication
Division
Addition
Subtraction
3(2+5)-5(3)+8=?
3(7)-5(3)+8=?
No exponents
3(7)-5(3)+8=?
21-15+8=?
No division
21-15+8=?
21-7=?
21-7=14
3(2+5)-5(3)+8=14
I'm thinking you would have to add the probabilities that you choose a boy with you choose someone in the science club minus a boy in the science club. You can't count these people twice.
I'm getting 59%
(11+10-2)/32
