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Leno4ka [110]
3 years ago
11

The highway mileage m in miles per gallon for a compact car is approximated by m(s) = -0.025s2 + 2.45s - 30, where s is the spee

d in miles per hour. What is the maximum mileage for this compact car to the nearest tenth of a mile per gallon?
Mathematics
1 answer:
kozerog [31]3 years ago
6 0
Highest mileage
m(s) = -0.025s2 + 2.45s - 30
This quadratic equation lokks like a upside down parabolla
So as it is a form of mileage gunction of speed, its maximum value should be K

The "a" in the vertex form "<span>y = a(x – h)2 + k</span>" of the quadratic is the same as the "a" in the common form of the quadratic equation, "<span>y = ax2 + bx + c</span><span>".
</span>

<span>To find the vertex, I look at the coefficients a<span>, </span>b<span>, and </span>c. The formula for the vertex gives me:<span>Y= -0.025s2 + 2.45s - 30
</span><span>h = <span>–b</span>/<span>2a</span> =  -2.45/2× -0.025=49</span><span>Put value of h to get K</span><span>k=-0.025(49)^2+2.45×(49)-30</span><span>k=  -30.025</span><span>k=  -</span>30.0<span>
</span></span>
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The diameters of bolts produced in a machine shop are normally distributed with a mean of 5.755.75 millimeters and a standard de
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P(<em>D</em> < <em>d</em>₂) = 0.94

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Convert <em>D</em> to a random variable <em>Z</em> following the standard normal distribution using

<em>Z</em> = (<em>D</em> - <em>µ</em>) / <em>σ</em>

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P(<em>D</em> < <em>d</em>₂) = P((<em>D</em> - 5.75) / 0.07 < (<em>d</em>₂ - 5.75) / 0.07)

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→   <em>d</em>₁ ≈ 5.64

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