Answer:
(2,1) aka D
Step-by-step explanation:
Answer:
1/2 of the jelly beans were either red or green.
Step-by-step explanation:
Of the 12 jellybeans, 1/3 were red, and 1/6 were green; this means the number of red jellybeans were
![\frac{1}{3} *12=4 \:red\:beans,](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D%20%2A12%3D4%20%5C%3Ared%5C%3Abeans%2C)
and the number of green jellybeans were
.
This means that we have 4+2=6 jellybeans that are either red or green. Now this 6 is
![\frac{6}{12} =\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B12%7D%20%3D%5Cfrac%7B1%7D%7B2%7D)
fraction of the total jelly beans.
Therefore 1/2 of the jellybeans were either red or green.
<em>The appropriate number of red and green jellybeans are colored in the figure attached.</em>
Answer:
may be its -6 units
Step-by-step explanation:
because if you count the number it will be-6
Answer:
a) The sequence of first three terms
5 , 8 , 13 ..
b) The
of the sequence
a₁₀ = 104
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Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given
term of the sequence
aₙ = n² + 4
put n=1
First term a₁ = 1² +4 = 1+5
put n =2
Second term a₂ = 2²+4 = 4+4 =8
Put n=3
Third term a₃ = 3² +4 = 9+4 =13
The sequence of first terms
5 , 8 , 13 ..
<u><em>Step(ii):-</em></u>
Given
term of the sequence
aₙ = n² + 4
put n =10
a₁₀ = 10²+4 = 100+4 = 104
a₁₀ = 104
The
of the sequence
a₁₀ = 104
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