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MakcuM [25]
3 years ago
5

Brian buys a computer for £4300. It depreciates at a rate of 3% per year. How much will it be worth in 6 years? Give your answer

to the nearest penny where appropriate.
Mathematics
2 answers:
Lady_Fox [76]3 years ago
7 0

Answer:

In 6 years, the cost of the computer would be £3581.2

Step-by-step explanation:

Brian buys a computer for £4300.. This means that the initial cost of the computer is £4300. It depreciates at a rate of 3% per year. Therefore, rate,

r = 3/100 = 0.03

Let x represent the amount that the computer depreciates to after t years. Therefore

Current amount = initial amount(1 - rate)^time. Therefore,

x = 4300(1 - 0.03)^6

x = 4300(0.97)^6 = £3581.2

aalyn [17]3 years ago
4 0

Answer:

3526

Step-by-step explanation:

4300×3%=129

129×6=774

4300_774= 3526

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Given that f.x 3x-2 over x+1 g[x] x +5 evaluate f[-4] and gf [-2]
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The value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

<h3>What is the value of f[-4] and g°f[-2]?</h3>

Given the function;

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  • g(x)=x+5
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For f[ -4 ], we substitute -4 for every variable x in the function.

f(x) = \frac{3x-2}{x+1}\\\\f(-4) = \frac{3(-4)-2}{(-4)+1}\\\\f(-4) = \frac{-12-2}{-4+1}\\\\f(-4) = \frac{-14}{-3}\\\\f(-4) = \frac{14}{3}

For g°f[-2]

g°f[-2] is expressed as g(f(-2))

g(\frac{3x-2}{x+1}) =  (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) =  \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) =  13

Therefore, the value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

Learn more about composite functions here: brainly.com/question/20379727

#SPJ1

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