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3 years ago

12

BRAINLIESTT ASAP! PLEASE HELP ME :) thanks!

1 answer:

slega [8]3 years ago

5 0

Answer:

option 1

Step-by-step explanation:

Corresponding parts of congruent triangles are equal or congruent

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How do you do this???????????????????

Akimi4 [234]

The volume of water that goes into the hose is the same as the volume of water that comes out the nozzle. This means the velocity is inversely proportional to the area. The area is proportional to the square of the diameter.

Taken together, these facts mean that if the diameter is divided by a factor of 3, the velocity is multiplied by a factor of 3^2 = 9.

Nozzle velocity = 3^2 * entering velocity
.. = 9 * (4 m/s)
Nozzle velocity = 36 m/s . . . . . . . . . corresponding to selection A

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3 years ago

If the volume of a spear is ?

Alla [95]

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6

Step-by-step explanation:

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2 years ago

Which statement best describes the effect of the confounding variable?

DiKsa [7]

Answer:

D

Step-by-step explanation:

6 0

2 years ago

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The newest cellular phone costs $784.26 after a 5.5% sales tax is applied. What is the cost of the cellular phone before sales t

Vladimir79 [104]

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3 0

3 years ago

A survey conducted by a leading HMO found that of 2000 women, 340 were heavy smokers and 25 had emphysema. Of those who had emph

belka [17]

Answer:

The events being a heavy smoker and having emphysema are not independent.

Step-by-step explanation:

We are given the following in the question:

Number of women = 2000

Number of heavy smoker = 340

Number of women who has emphysema = 25

Number of women who has emphysema and are heavy smoker = 21

$\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}$

P(Smoker) =

$P(S) = \dfrac{340}{2000}=0.17$

P(emphysema) =

$P(E) = \dfrac{25}{2000}= 0.0125$

P(Smoker and emphysema) =

$P(S\cap E) = \dfrac{21}{2000} = 0.0105$

Two events A and B are said to be independent if

$P(A\cap B)=P(A)\times P(B)$

Checking conditions for independence:

$P(S)\times P(E) = 0.17\times 0.0125=0.002125\\P(S)\times P(E) \neq 0.0105\\P(S)\times P(E)\neq P(S\cap E)$

Thus, the events being a heavy smoker and having emphysema are not independent.

3 0

3 years ago