2 years ago

A woman rides a bicycle for 1 hour and travels 12 kilometers. Find the angular velocity of the wheel if the radius

Mathematics

1 answer:

Korolek [52]2 years ago

3 0

14.81 radians/second

Step-by-step explanation:

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Tell whether the angles are adjacent or vertical. Then find the value of $x$ .

boyakko [2]

Answer:

they are adjacent angles

Step-by-step explanation:

for adjacent angles

${(x + 3)}^{o} = {84}^{0} \\ x = 84 - 3 \\ x = 81$

7 0

2 years ago

Determine the Intercepts of the line.<br><br> Y-intercept: (__,__)<br> X-intercept: (__,__)

vagabundo [1.1K]

Answer:

I think the answer is 0.3 in 0.4

5 0

2 years ago

What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove

wolverine [178]

Answer:

The solutions are:

$b=0,\:b=4$

Step-by-step explanation:

Considering the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

Solving the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

$\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c$

$5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2$

$5b^3-10=6b^3-4b^2-10$

$\mathrm{Switch\:sides}$

$6b^3-4b^2-10=5b^3-10$

$6b^3-4b^2-10+10=5b^3-10+10$

$6b^3-4b^2=5b^3$

$\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}$

$6b^3-4b^2-5b^3=5b^3-5b^3$

$b^3-4b^2=0$

$Using\:the\:Zero\:Factor\:Principle:$ $if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

So,

$b=0,b-4=0$

$b=0,b=4$

Therefore, the solutions are:

$b=0,\:b=4$

4 0

3 years ago

Read 2 more answers

At a shelter 15%of the dogs are puppies. There are 60 dogs at the shelter. How many are puppies???? Will Mark BRAINLLEST

tankabanditka [31]

Answer:

there are 9 puppies.

Step-by-step explanation:

Hope this helps! Happy Trails!

8 0

3 years ago

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Write the quadratic equation whose roots are 3 and -5, and whose leading coefficient is 2.

Rainbow [258]

$\begin{cases} x=3\implies &x-3=0\\ x=-5\implies &x+5=0 \end{cases}\qquad \implies\qquad a(x-3)(x+5)=\stackrel{0}{y} \\\\\\ a(\stackrel{F~O~I~L}{x^2+2x-15})=y\implies \stackrel{\textit{leading coefficient of 2}}{2(x^2+2x-15)}=y\implies 2x^2+4x-30=y$

Check the picture below.

5 0

2 years ago