Ask question

Ask question

All categories

3 years ago

12

Johnathan has been driving at a constant speed for 4 hours, during which time he traveled 240 miles Johnathan world like to know

how long it will take him to complete the remaining 360 miles, assuming he maintains the same constant speed.

1 answer:

valentinak56 [21]3 years ago

8 0

30000000000000000000000000000000000

You might be interested in

Help help math math math math math

chubhunter [2.5K]

<h3>Answer: y - 4 = -2(x - 5)</h3>

==================================================

Explanation:

Point slope form is

y - y1 = m(x - x1)

where m is the slope and (x1,y1) is the point the line goes through.

Parallel lines have equal slopes but different y intercepts. The given equation y = -2x-3 has a slope of -2, meaning that m = -2 is also the slope of the mystery parallel line.

-2 will go in the second box that's just to the left of the parenthesis.

The coordinates of (5, 4) will go in the other remaining boxes to finish off the equation.

We go from this

y - y1 = m(x - x1)

to this

y - 4 = -2(x - 5)

5 0

3 years ago

Are these right before I go on I have a 100 in math #wannakeepit

Serjik [45]

They are all correct

4 0

3 years ago

If anyone knows about definite integrals for calculus then please I request help! I

kicyunya [14]

Answer:

$\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)$

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Integration

Integrals

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

U-Substitution

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

$\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx$

<u>Step 2: Integrate Pt. 1</u>

<em>Identify variables for u-substitution.</em>

Set <em>u</em>: $\displaystyle u = 4x^{-2}$
[<em>u</em>] Differentiate [Basic Power Rule, Derivative Properties]: $\displaystyle du = \frac{-8}{x^3} \ dx$
[Bounds] Switch: $\displaystyle \left \{ {{x = 9 ,\ u = 4(9)^{-2} = \frac{4}{81}} \atop {x = 5 ,\ u = 4(5)^{-2} = \frac{4}{25}}} \right.$

<u>Step 3: Integrate Pt. 2</u>

[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^9_5 {\frac{-8}{x^3}e^\big{4x^{-2}}} \, dx$
[Integral] U-Substitution: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^{\frac{4}{81}}_{\frac{4}{25}} {e^\big{u}} \, du$
[Integral] Exponential Integration: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}(e^\big{u}) \bigg| \limits^{\frac{4}{81}}_{\frac{4}{25}}$
Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8} \bigg( e^\Big{\frac{4}{81}} - e^\Big{\frac{4}{25}} \bigg)$
Simplify: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

4 0

2 years ago

..................

sveticcg [70]

Answer:

y = 100°

Step-by-step explanation:

x = 40° (vertical angles are congruent)

y is an exterior angel of a triangle that has two opposite internal angles, x (40°) and 60°.

According to the exterior angle of a triangle, thus:

y = 40 + 60

y = 100°

3 0

3 years ago

Nico can do 42 push-ups in 3 minutes.

Alchen [17]

Step-by-step explanation:

Hey there!

It is said we need to find the unit rate.

What we can do is apply Unitary Method.

3 minutes = 42 push ups

1 minute = $\sf{\bf{\dfrac{42}{3}}}$

<u>So, 12 push ups per minute is the unit rate.</u>

In 5 minutes, he will do 12×5 = <u>60 push ups!</u>

Hope it helps :)

4 0

3 years ago