If one of the numbers we multiply (factors) has zeros at the end, and the other isn't a fraction: all those zeros will stay in the product.
But there might be additional zeros if the other numbers in the factors (the numbers which aren't 0) mupliply to "end" in zero and this is the case here:
8*5=40.
so the product will be 40 and the zeros of the 5000:
40 000
the number of zeros in the product will be bigger than the number of zeros in the factors if the non-zero parts of the fractions multiply to a number with 0 at the end.
Try to refrain from asking more than three questions per question for future reference.
11+4=15
6+4=10
4+7=11
12+4=16
0+4=4
4+0=4
10+4=14
4+5=9
9+4=13
4+2=6
4+8=12
4+3=7
7+4=11
4+4=8
4+1=5
8+4=12
Hope this helps.
-Benjamin
A is the correct answer to this question because AC and BC differ because the B must be changed to an A.
I can't see the whole diagram.. Can u fix the picture
