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Elden [556K]
3 years ago
14

The mean and the median are the same. 2,3,4,5

Mathematics
1 answer:
Ber [7]3 years ago
7 0

Step-by-step explanation:

mean \: ( \bar  x) =  \frac{2 + 3 + 4 + 5}{4}  =  \frac{14}{4}  = 3.5 \\  \\ median \: =  \frac{3 + 4 }{2}  =  \frac{7}{4}  = 3.5 \\  \\

Thus, mean and median are same.

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The combined area of two squares is 17 square meters. the size of the larger Square are four times as long as the size of the sm
7nadin3 [17]

we are given that ,

The combined area of two squares is 17 square meters.

Area of square=(side)^2

Let the side length of smaller square be x

The size of the larger Square are four times as long as the size of the smaller square

Area \ of  \ smaller \ square \ =x^2

So Area of larger square=4x^2

The combined Area is 17 square meter.

x^2+4x^2=17\\\\5x^2=17\\\\x=\sqrt{\frac{17}{5}}

Hence the smaller square has the side length=\sqrt{\frac{17}{5}}

So the larger square has side length=2\sqrt{\frac{17}{5}}

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3 years ago
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Marat540 [252]
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7 0
2 years ago
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MArishka [77]

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8 0
3 years ago
1/8 of the boys at a high school tried out for the football team, 1/6 tried out for the baseball team, and 1/ 12 tried out for t
Xelga [282]

Answer:

2/3

Step-by-step explanation:

This problem is an overlap problem. First we have that 1/8 total tried out for football team, 1/6 total tried out for baseball team and 1/12 of the students that tried out for both football and baseball team.

So if we want to find those who just tried football, we perform the following operation:

1/8 - 1/12 = 1/24.

So we know that 1/24 tried out just football.

If we want to find all those who tried out just for baseball, we perform the following operation:

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So we know that 2/24 (1/12 multiplied by two) tried  for both football and baseball and 3/24 tried out for football, it means that 2/3 of the boys who tried football also tried baseball.

7 0
3 years ago
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