Question

The combined area of two squares is 17 square meters. the size of the larger Square are four times as long as the size of the smaller square. find the dimensions of each of the squares

Answer 1

we are given that ,

The combined area of two squares is 17 square meters.

Area of square=$(side)^2$

Let the side length of smaller square be x

The size of the larger Square are four times as long as the size of the smaller square

$Area \ of \ smaller \ square \ =x^2$

So Area of larger square=$4x^2$

The combined Area is 17 square meter.

$x^2+4x^2=17\\\\5x^2=17\\\\x=\sqrt{\frac{17}{5}}$

Hence the smaller square has the side length=$\sqrt{\frac{17}{5}}$

So the larger square has side length=$2\sqrt{\frac{17}{5}}$