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shutvik [7]
3 years ago
14

How do you find the total sum of squared values?

Mathematics
1 answer:
tester [92]3 years ago
7 0

Answer:

Step-by-step explanation:

\sum^{12}_{r=1} r^2 = \frac{12(12+1)(2*12+1)}{6}= A

\sum_{r=3}^{12}= \sum_{r=1}^{12} - (r_1+r_2)

r_1= 1^2

r_2= 2^2

you do your math!!

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Lettets a, b, c, and d are angle measures Which should equal 105 to prove false g
GrogVix [38]

Answer:

a equals 105°

Step-by-step explanation:

angles in a straight line add up to 180°

a+75=180

a=180-75

a=105°

4 0
3 years ago
PLEASEEEEEE HELPPPP!!!!
pogonyaev
I believe this would be correct.

6 0
3 years ago
Read 2 more answers
A package of 5 pairs of insulated socks costs ​$26.45. What is the unit price of the pairs of socks​?
tigry1 [53]

Answer:

$5.29 per pair of socks

Step-by-step explanation:

26.45/5=5.29

3 0
2 years ago
If <img src="https://tex.z-dn.net/?f=%20300cm%5E%7B2%7D%20" id="TexFormula1" title=" 300cm^{2} " alt=" 300cm^{2} " align="absmid
Artist 52 [7]
Check the picture below.  Recall, is an open-top box, so, the top is not part of the surface area, of the 300 cm².  Also, recall, the base is a square, thus, length = width = x.

\bf \textit{volume of a rectangular prism}\\\\&#10;V=lwh\quad &#10;\begin{cases}&#10;l = length\\&#10;w=width\\&#10;h=height\\&#10;-----\\&#10;w=l=x&#10;\end{cases}\implies V=xxh\implies \boxed{V=x^2h}\\\\&#10;-------------------------------\\\\&#10;\textit{surface area}\\\\&#10;S=4xh+x^2\implies 300=4xh+x^2\implies \cfrac{300-x^2}{4x}=h&#10;\\\\\\&#10;\boxed{\cfrac{75}{x}-\cfrac{x}{4}=h}\\\\&#10;-------------------------------\\\\&#10;V=x^2\left( \cfrac{75}{x}-\cfrac{x}{4} \right)\implies V(x)=75x-\cfrac{1}{4}x^3

so.. that'd be the V(x) for such box, now, where is the maximum point at?

\bf V(x)=75x-\cfrac{1}{4}x^3\implies \cfrac{dV}{dx}=75-\cfrac{3}{4}x^2\implies 0=75-\cfrac{3}{4}x^2&#10;\\\\\\&#10;\cfrac{3}{4}x^2=75\implies 3x^2=300\implies x^2=\cfrac{300}{3}\implies x^2=100&#10;\\\\\\&#10;x=\pm10\impliedby \textit{is a length unit, so we can dismiss -10}\qquad \boxed{x=10}

now, let's check if it's a maximum point at 10, by doing a first-derivative test on it.  Check the second picture below.

so, the volume will then be at   \bf V(10)=75(10)-\cfrac{1}{4}(10)^3\implies V(10)=500 \ cm^3

6 0
3 years ago
What is 9+5x-5+3x? What could it be
qwelly [4]
8x+4 would be the answer if you combine like terms
6 0
3 years ago
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