Question

How do you find the total sum of squared values?

Answer 1

Answer:

Step-by-step explanation:

$\sum^{12}_{r=1} r^2 = \frac{12(12+1)(2*12+1)}{6}= A$

$\sum_{r=3}^{12}= \sum_{r=1}^{12} - (r_1+r_2)$

$r_1= 1^2$

$r_2= 2^2$

you do your math!!