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shutvik [7]
2 years ago
14

How do you find the total sum of squared values?

Mathematics
1 answer:
tester [92]2 years ago
7 0

Answer:

Step-by-step explanation:

\sum^{12}_{r=1} r^2 = \frac{12(12+1)(2*12+1)}{6}= A

\sum_{r=3}^{12}= \sum_{r=1}^{12} - (r_1+r_2)

r_1= 1^2

r_2= 2^2

you do your math!!

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Solve the inequality x-4 < - 3.Then graph the solution set.show your work.
bearhunter [10]

Answer:

x < 1

Step-by-step explanation:

x - 4 < - 3

<u>  + 4    +4</u>                        Do inverse operations by adding 4 on both sides

    x < 1

Therefore, the answer is x < 1.

(It isn't allowing me to attach a photo but I am just going to try make a visual of the graph below)

<------------------------------o------------------>

-4    -3    -2    -1     0    1     2    3      4

The circle is open because based on the concept that in inequalities, <em>less/greater than and/or equal to (such as these ≥ ≤ )</em> signs are graphed with closed circles, while less/greater than (like these > <) signs are graphed with open circles. The direction of the arrow is moving to the left on the number line because all possible values for x would be less than 1. When graphing the inequality you would use a solid line rather than a dashed line (I had to improvise since I could not attach an image).

8 0
2 years ago
Find the slope of the line passing through the points (-9, -6) and (-4, 5).
Goryan [66]

Answer:

m=\frac{11}{5}

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Find the break-even point for the given cost and revenue equations. Round to the nearest whole unit. C = 20n + 134,000 R = 160n
Harman [31]
At break-even C = R so we have:-

20n + 134,000 = 160n

140n = 134,000

answer = 134,000 / 140  =  957
8 0
2 years ago
5.476 rounded to the hundredths place
Murrr4er [49]
5.476 rounded to the hundredths place = 5.48
5 0
3 years ago
Read 2 more answers
For two events and , the probability that occurs is 0.8, the probability that occurs is 0.4, and the probability that both occur
sergey [27]

Answer:

P(B|A)=0.25  , P(A|B) =0.5

Step-by-step explanation:

The question provides the following data:

P(A)= 0.8

P(B)= 0.4

P(A∩B) = 0.2

Since the question does not mention which of the conditional probabilities need to be found out, I will show the working to calculate both of them.

To calculate the probability that event B will occur given that A has already occurred (P(B|A) is read as the probability of event B given A) can be calculated as:

P(B|A) = P(A∩B)/P(A)

      = (0.2) / (0.8)  

P(B|A)=0.25

To calculate the probability that event A will occur given that B has already occurred (P(A|B) is read as the probability of event A given B) can be calculated as:

P(A|B) = P(A∩B)/P(B)

          = (0.2)/(0.4)

P(A|B) =0.5

7 0
3 years ago
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