. An object dropped from a height of 200 meters has a height, h(t), in meters after t seconds have lapsed, such that h(t) = 200
– 4.9t2. Express t as a function of height, h, and find the time to reach a height of 50 meters.
1 answer:
Answer:
t(h)= (h-200)/-4.9
The time to reach a height of 50 meters is 30.6 seconds
Step-by-step explanation:
To express t as a function of height (h) we must transform the equation below:
h=200-4.9t
h-200=-4.9t
(h-200)/-4.9=t
t(h)= (h-200)/-4.9
To find the time to reach a height of 50 meters, we must replace this value on the new equation:
t(h)=50-200/-4.9
t(h)= 30.612
The time to reach a height of 50 meters is 30.6 seconds
You might be interested in
Answer
idk
Step-by-step explanation:
WHY T F
ARE THEY USING LETTERS IN MATH
The point (0, 8) simply means the x axis is 0 while the y axis is 8. The answer is C.
Answer:
The distance of the point P(-6, 8) from the origin is
OP2=(-6)2+82=36+64=100⇒OP=√100=10 units
Solve for the first variable in one the equations then substitute the result into the other equation so the answer is (2,5)
Answer:
1. Intersecting
2. Transversal
3. Adjacent