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2 years ago

What is the measure of x?

Mathematics

2 answers:

zalisa [80]2 years ago

6 0

Answer:

138 degrees, hope this helps :)

Step-by-step explanation:

Goryan [66]2 years ago

3 0

Answer:

x=138°

Step-by-step explanation:

x=70°+68°=138°

The outer angle is equal to the sum of the two non-adjacent angles

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CAN SOMEONE PLEASE HELP!!! :c thank you in advance!

KiRa [710]

Lines A and B are parallel to each other. Lines B and E are perpendicular to each other.

4 0

3 years ago

Find a compact form for generating functions of the sequence 1, 8,27,... , k^3

pantera1 [17]

This sequence has generating function

$F(x)=\displaystyle\sum_{k\ge0}k^3x^k$

(if we include $k=0$ for a moment)

Recall that for $|x|$ , we have

$\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k$

Take the derivative to get

$\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k$

$\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k$

Take the derivative again:

$\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k$

$\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k$

Take the derivative one more time:

$\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k$

$\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k$

so we have

$\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}$

5 0

3 years ago

ANSWER PLLLLEEEEAAASSSEEE

Whitepunk [10]

Answer:

30%

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

HELLO CAN ANYONE HELP MEE PLEASE I DONT UNDERSTAND!!

Furkat [3]

Answer:

−143x^3y^5

Step-by-step explanation:

7 0

3 years ago

Please help. Thank you

shepuryov [24]

complementary is 90 degrees. so, you combine like terms.

7 0

2 years ago