2x plus 1 worded in algebraic expression

The parallelogram is divided into two triangles. Remember, angles in a triangle add up to 180 degrees. That being said, take the sum of the numbers given in triangle ABC and subtract it from 180.

60 + 28 = 88

180 - 88 = 92 (this is the measure of angle B)

Angles D and B are congruent, which means they are the same.

Since Angle B is 92 degrees, then D is 92 degrees also.

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3 years ago

What is the shape callled that looks like a rectangle with two sides that look like a triangle

Softa [21]

Quadrangle
A quadrilateral can sometimes be called: a Quadrangle ("four angles"), so it sounds like "triangle"
Please Mark Brainliest.

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3 years ago

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How can you find the equation of a line that is parallel/perpendicular to a given line

alexdok [17]

In the Slope-Intercept Form, m is the slope and b is the y-intercept.

<u>Finding The Equation of a Line Parallel to the Given Line:</u> Let the given line be line a and the parallel line be line b.

1) Find the slope of line a.

Example: Line a --> $y = 5x + 2$ . The slope is 5.

2) Find the y-intercept of line b.

To do this, you need to be given the coordinates of a point located on line b.

Example: The slope is 5 and the point is (2, 3), use the Slope-Intercept Formula, $y=mx+b$ ---> $3 = 5(2) + b$ . Then you solve for b.

$3 = 5(2) + b$

$3 = 10 + b$

$3 - 10 = 10 - 10 + b$

$-7 = b$ $b=-7$

The y-intercept of line b is -7

3) Finally, plugin the slope and the y-intercept into the Slope-Intercept Form.

Example: The slope of line b is 5 and the y-intercept is -7. The equation of line b is $y = 5x - 7$ .

<u>Finding The Equation of a Line Perpendicular to The Given Line:</u> Let the given line be line a and the perpendicular line be line b.

1) Find the opposite reciprocal of the slope of line a.

Example: Line a --> $y=5x+2$ . The slope is 5, to find the opposite reciprocal of the slope you use n --> $-\frac{1}{n}$ . In this case, it would be $-\frac{1}{5}$ . The opposite reciprocal of the slope of line a is $-\frac{1}{5}$ , which would be the slope of line b.

2) Find the y-intercept of line b.

To do this, you need to be given the coordinates of the point where line a and line b both intersect.

Example: The slope of line b is $-\frac{1}{5}$ and the point is (1, 7), use the Slope-Intercept Formula, $y=mx+b$ ---> $7=-\frac{1}{5}(1) + b$ . Then you solve for b.