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gulaghasi [49]
3 years ago
5

Helpppppppppppp meeeeeeeeee

Mathematics
1 answer:
KatRina [158]3 years ago
5 0

Answer:

X=-1

Step-by-step explanation:

X=-1 is just a vertical line since it only tells where the x point is.

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14. Betty is making a mixed fruit punch for her birthday party on Saturday. The recipe requires 3 cups of
Westkost [7]

Answer:

ten and a half

Step-by-step explanation:

2×3.5= 7

3×3.5= 10.5

8 0
3 years ago
Pls look at the photo and identify the extrema pls! I only have one try left!!
dusya [7]
A C and F those would be the correct answers girlie
3 0
3 years ago
This is the easiest question
Arturiano [62]

Answer:  3\dfrac{2}{6}\ h

Step-by-step explanation:

Given

Rami practices his saxophone for \frac{5}{6} hour on 4 day each week

So, for a week she practices around

\Rightarrow \dfrac{5}{6}\times 4\\\\\Rightarrow \dfrac{20}{6}

Converting it into mixed fraction

\Rightarrow \dfrac{20}{6}=\dfrac{18+2}{6}\\\\\Rightarrow 3\dfrac{2}{6}\ h

5 0
3 years ago
A high schools basketball team won 36 percent of the games that played last season . The team won exactly 9 games last season .
Elenna [48]
25 games. 0.36x (where is the total number of games)=9. divide by 0.36 on both sides which ends up with 25.
4 0
4 years ago
Simplify this equation please.
Sauron [17]
\dfrac{\csc^2\theta-3\csc\theta+2}{\csc^2\theta-1}

Identity:

\sin^2\theta+\cos^2\theta=1\implies1+\cot^2\theta=\csc^2\theta

So we can rewrite the denominator to get

\dfrac{\csc^2\theta-3\csc\theta+2}{\cot^2\theta}

Multiply numerator and denominator by \sin^2\theta. Several terms will cancel since \sin\theta\csc\theta=1. Also, \cot\theta=\dfrac{\cos\theta}{\sin\theta}. We get

\dfrac{1-3\sin\theta+2\sin^2\theta}{\cos^2\theta}

Factorize the numerator, and write \cos in terms of \sin in the denominator to factorize it further to get

\dfrac{(1-\sin\theta)(1-2\sin\theta)}{\cos^2\theta}=\dfrac{(1-\sin\theta)(1-2\sin\theta)}{1-\sin^2\theta}=\dfrac{(1-\sin\theta)(1-2\sin\theta)}{(1-\sin\theta)(1+\sin\theta)}


The 1-\sin\theta factors cancel, leaving you with

\dfrac{1-2\sin\theta}{1+\sin\theta}

which you could simplify a bit further by writing

\dfrac{1+\sin\theta-3\sin\theta}{1+\sin\theta}=1-\dfrac{3\sin\theta}{1+\sin\theta}
3 0
4 years ago
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