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3 years ago

10

There were 532 people at the Nutcracker. If admission was $24 for adults and $16 for children and $10,272 was collected, how man

y adults and children attended? Write a system of equations and a solution statement.

1 answer:

anzhelika [568]3 years ago

4 0

X = # adults

y = # children

system

24x+16y=$10272
x + y =532

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Answer: The net weight of the pigs of the truck is 1 ton 868 pounds 12 ounces.

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Step-by-step explanation:

Since we have given that

The gross weight of a truck containing 30 pigs = 8 tons 1123 pounds 6 ounces

Average weight of one pig = 95 pounds 10 ounces

Now,

We know that

$1\text{ pound}=16\text{ ounces}$

So,

$\text{Gross weight of truck containing 30 pigs}\\=8\text{ tones }1123\times 16+6\text{ ounces}\\=8\text{ tons }17974\text{ ounces}$

Similarly,

$\text{ average weight of one pig }\\=95\times 16+10\text{ ounces}\\=1530\text{ ounces}$

So, Net weight of the pigs in the truck

$1530\times 30\\ =45900\text{ ounces}\\\\=\frac{45900}{16}\\\\=2868\text{ pounds }12\text{ ounces}\\\\=1\text{ ton }868\text{ pounds }12\text{ ounces }$

So, the net weight of the pigs of the truck is 1 ton 868 pounds 12 ounces.

Now, we'll find the weight of the empty truck is given by

$\text{Gross weight of a truck containing} -\text{ Net weight of pigs in the truck}\\=8\text{ tons}1123\text{ pounds}6\text{ ounces}-1\text{ton }868\text{ pounds }12\text{ounces}\\=(8\times 2000\times 16+1123\times 16+6)-(1\times 2000\times 16+868\times 16-12)\\=273974\text{ ounces}-45900\text{ ounces}\\=228074\text{ounces }\\=7\text{ tons }254\text{ pounds }10\text{ ounces}$

Hence, the weight of the empty truck is 7 tons 254 pounds 10 ounces .

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