X^2(x+2)-4(x+2)
(x^2-4) (x+2) = 0
do you have to keep going/?
or thats all they want?
Answer:
-4 and 0
Step-by-step explanation:
Rise over Run would give us the slope.
In the first graph, It goes down 4 while it goes 1 to the right.
This means that -4/1 = -4.
The second graph does not go up or down, meaning 0, while it goes 1 to the right.
This means that 0/1 = 0.
Answer: 5x (x-3) or 5(x^2-3x)
Step-by-step explanation:
Given equation is

The given equation is in the form of

a^2= 16 , so a=4
b^2 = 9 so b= 4
The value of 'a' is greater than the value of 'b'
So it is a Horizontal hyperbola
First two graphs are horizontal hyperbola
Here center is (h,k)
h= 5 and k =2 from the given equation
So center is (5,2)
Now we find vertices
Vertices are (h+a,k) and (h-a,k)
We know h=5, k=2 and a=4
So vertices are (9,2) and (1,2)
Second graph having same vertices and center
The correct graph is attached below
Vertex Q is 6 units from vertex R
Vertex R is 7 units from vertex T
Vertex T is 3 units from vertex S