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3 years ago

PLZ HELP

Mathematics

1 answer:

Masja [62]3 years ago

3 0

Answer:

B. Survey 1,000 people aged below 25 who read newspapers

Step-by-step explanation:

It's the youth in the community so it's obviously people below 25 and we need more responses to get a more unbiased opinion.

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What are the first three terms of a geometric sequence in which (picture below) and the common ratio is 5?

Marta_Voda [28]

Answer:

5, 10, 15

Step-by-step explanation:

the increase in the sequence is 5 so since it starts from 0 which you can find out because 25 is the 5th sequence and that means that +2*5 =25 . x=0

0+ 5 = sequence 1

0+ 5+5 = seq 2

0+5+5+5= seq 3

5 0

2 years ago

What is six times more than three times a number is that number increased by 24. Find the number. Write an equation. And find x

Lubov Fominskaja [6]

Given the information, you can only write an expression and simplify it:

6(3(x+24))

6(3x+72)

SOlution: 18x+432

I hope I helped you with your solution! If you could give me brainliest, I would be very thankful!

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3 years ago

In the problem: 3,699 divided by 9 = 411, the number that is the DIVIDEND is_____. *

Shkiper50 [21]

Answer:

Step-by-step explanation:

4 0

3 years ago

7. The probability that Jane smokes is 4/9. The probability

svet-max [94.6K]

To find the probability that she develops lung cancer given that she smokes, multiply the two probabilities together:

4/9 x 3/10 = (4 * 3) / (9*10) = 12/90 = 2/15

6 0

3 years ago

Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be

Oksana_A [137]

<h2>Hello!</h2>

The answers are:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

To calculate the speed of the cars, we need to write two equations, one for each car, in order to create a relation between the two speeds and be able to calculate one in function of the other.

So,

Tet be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

$x_{FirstCar}=x_o+v*t$

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

$x_{SecondCar}=x_o+(v+14mph)*t$

Now, from the statement that both cars met after 2 hours and 45 minutes, and the distance between to cover (between A and B) is 264 miles, so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

$RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph$

Then, since we know that they covered a combined distance equal to 264 miles in 2 hours + 45 minutes, we have:

$2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours$

Writing the equation:

$264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph$

So, the speed of the first car is equal to 41 mph.

Now, for the second car we have that:

$SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph$

We have that the speed of the second car is equal to 55 mph.

Hence, the answers are:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

Have a nice day!

7 0

3 years ago