Answer:
1.what number should be added to both sides of the equation? 1
2. how many of the solutions to the equation are positive? one, x=3.031
3.what is the approximate value of the greatest solution to the equation rounded to the nearest hundredth? 3.03
Step-by-step explanation:
The question is on solving for quadratic equations using the completing square method
The equation given is ;
4x²+8x+27=88...........rewrite the equation
4x²+8x+27-88=0
4x²+8x+-61=0...................divide every term of the equation by 4
4x/4²+8x/4+-61/4=0/4
x²+2x-15.25=0..................rewrite the equation as;
x²+2x=15.25.......................complete square on both sides
x²+2x+ (2/2)²= 15.25 +(2/2)²
x²+2x+1 = 15.25+1
x²+2x+1=16.25................factorize the left hand side
(x+1)²=16.25.....................eliminate the root on the left hand side
x+1=±√16.25
x+1= ± 4.031
solutions
x+1= +4.031
x= +4.031-1 =3.031
or
x+1= -4.031
x= -4.031-1 = - 5.031
1. 3
2. 4
3. 1
4. 48
5. 6
6. 108
7. 7.5
8. 66
9. 216
10. 12
11. 3.75
12. 30
Anytime buddy ;)
Step-by-step explanation:
Raquel has gross pay of $732 and federal tax withholdings of $62. Determine Raquel’s net pay if she has the additional items withheld: Social Security tax that is 6. 2% of her gross pay Medicare tax that is 1. 45% of her gross pay state tax that is 21% of her federal tax a. $600. 99 b. $610. 54 c. $641. 83 d. $662. 99.
Answer:
2.75s + 2w ≤ 15
3 waters
2.75s + 2(3) ≤ 15
2.75 + 6 ≤ 15
Subtract 6 from both sides
2.75s ≤ 9
Divide both sides by 2.75
s ≤ 3.27
since you can't by a negative amount of soda
0 ≤ s ≤ 3.27
But you also can't buy part of a soda
0 ≤ s ≤ 3 <------
Hope this helps?
The complete question in the attached figure
Part A) find the perimeter
[perimeter of the garden]=[perimeter square 1]+[perimeter a quarter circle]+[perimeter square 2]
[perimeter square 1]=5+5+5-----> 15 ft
[perimeter square 2]=5+5+5-----> 15 ft
[perimeter a quarter circle]=(2*pi*r)/4------> 2*pi*5/4-----> 7.85 ft
[perimeter of the garden]=[15]+[7.85]+[15]-------> 37.85 ft
the answer Part A) isthe perimeter of the garden is 37.85 ftPart B) Find the area of the garden
[Area of the garden]=[Area square 1]+[Area a quarter circle]+[Area square 2]
[Area square 1]=5*5-----> 25 ft²
[Area square 2]=5*5-----> 25 ft²
[Area a quarter circle]=(pi*r²)/4------> pi*5²/4-----> 19.625 ft²
[Area of the garden]=[25]+[19.625]+[25]-------> 69.625 ft²
the answer Part B) isthe Area of the garden is 69.625 ft²