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3 years ago

Help me I NEED HELP ASAP

Mathematics

1 answer:

emmasim [6.3K]3 years ago

4 0

Kk i will emailu for what i new flop

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Write the expression as a single natural logarithm.<br> 2 ln m + 9 ln n=in?

Akimi4 [234]

Answer:

ln (m^2n^9)

Step-by-step explanation:

Rule: ln a + ln b = ln ab

Rule: ln a^n = n * ln a

2 ln m + 9 ln n =

= ln m^2 + ln n^9

= ln (m^2n^9)

= $\ln m^2n^9$

7 0

3 years ago

Divide 5/9 round to the nearest tenth

zhenek [66]

Answer:

0.55

Step-by-step explanation:

5 divided by 9 = 0.55

3 0

3 years ago

Read 2 more answers

The expression 3x^3-5x^2+3x-1 has ___ terms and a constant of ____.

Andrews [41]

<span>The expression 3x^3-5x^2+3x-1 has ___ terms and a constant of ____.
have four terms and 1 constant
</span>

5 0

3 years ago

[30 POINTS] Please help!!!

Len [333]

Answer:

Part 1) $y=1.5x+5$

Part 2) $y=-(2/3)x-(11/3)$

Part 3) $y=0.25x+2.75$

Part 4) $y=-2x+5$

Part 5) $y=0.5x-1$

Part 6) The graph in the attached figure

Step-by-step explanation:

Part 1) we have

$m=3/2=1.5$

$point(-2,2)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-2=1.5(x+2)$

$y=1.5x+3+2$

$y=1.5x+5$

Part 2) we know that

If two lines are perpendicular

then

the product of their slopes is equal to minus one

$m1*m2=-1$

the slope of the line 1 is equal to

$m1=1.5$

Find the slope m2

$1.5*m2=-1$

$m2=-2/3$

Find the equation of the line 2

we have

$m2=-2/3$

$point(-7,1)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-1=(-2/3)(x+7)$

$y=-(2/3)x-(14/3)+1$

$y=-(2/3)x-(11/3)$

Part 3) we have

$m=1/4=0.25$

$point(1,3)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-3=0.25(x-1)$

$y=0.25x-0.25+3$

$y=0.25x+2.75$

Part 4) we have

$m=-2$

$b=5$ -----> y-intercept

we know that

The equation of the line into slope intercept form is equal to

$y=mx+b$

substitute the values

$y=-2x+5$

Part 5) we have that

The slope of the line 4 is equal to $-2$

the slope of the line perpendicular to the line 4 is equal to

$-2*m=-1\\m=(1/2)=0.5$

therefore

in this problem we have

$m=0.5$

$point(-2,-2)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y+2=0.5(x+2)$

$y=0.5x+1-2$

$y=0.5x-1$

Part 6)

using a graphing tool

see the attached figure

3 0

3 years ago

Helpppooo meeeee. !!!!!

Brrunno [24]

Answer:

The looks of the Triangles are different.

Step-by-step explanation:

3 0

3 years ago