Answer:
a = 2, b = - 6, c = 11
Step-by-step explanation:
The standard form of a quadratic equation is
ax² + bx + c = 0 : a ≠ 0
Compare the coefficients of the terms in standard form to
2x² - 6x + 11 = 0 ← in standard form
Thus a = 2, b = - 6 and c = 11
Answer:
75% gained
Step-by-step explanation:
75% of 2 is 1.5
Answer:
Yes, they are congruent
Step-by-step explanation:
Yes, they are congruent because all the side and angle lengths are congruent.
Answer:
3.
Step-by-step explanation:
Note the prime factorization of 120,

Therefore, there are 3 distinct prime factors, namely 2, 3 and 5.
Answer:
B) ∠B ≅ ∠K
Step-by-step explanation:
The Angle-Angle-Side Postulate (AAS) states that if two angles and a non-included side of one triangle are congruent to two angles and the corresponding non-included side of another triangle, then the two triangles are congruent.
Given that ∠A ≅ ∠J and AC ≅ JL, then we need that ∠B ≅ ∠K to satisfy postulate AAS (the two angles are ∠A and ∠B in one triangle and ∠K and ∠J in the other one, and the non-included side is AC in one triangle and JL in the other one).