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3 years ago

4.2y+0.8=6.2y–(1.1y+0.8)+1.2

Mathematics

2 answers:

Flura [38]3 years ago

7 0

4.2y + 0.8 = 6.2y - (1.1y + 0.8) + 1.2

Multiply/distribute the - into (1.1y + 0.8)

4.2y + 0.8 = 6.2y - 1.1y - 0.8 + 1.2

Combine like terms

4.2y + 0.8 = 5.1y + 0.4

Subtract 4.2y on both sides

0.8 = 0.9y + 0.4

Subtract 0.4 on both sides

0.4 = 0.9y

Divide 0.9 on both sides

$\frac{0.4}{0.9} = y$

s344n2d4d5 [400]3 years ago

3 0

Y=4/9...(tell me if you need steps)

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3 years ago

Which expression is equivalent to (8^2)^-4

xz_007 [3.2K]

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$a^{-n} = \frac{1}{a^n}$

Since a = $8^2$ :

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3 years ago

The Best Company produces two commercial products : blenders and mixers. Both products require a two step production process inv

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Answer:

Maximum profit is $87 when 3 blenders and 11 mixers are produced.

Step-by-step explanation:

let blender is represented by $x_{1}$ and and mixer by $x_{2}$ .

total time to deliver parts = 24 hrs

total time to assemble = 30 hrs

time taken by each blender to deliver parts = 1 hr

time taken by each mixer to deliver parts = 2 hr

time taken by blenders in final assembling= 2 hr

time taken by mixers in final assembling = 3 hr

Each blender produced nets the firm= $7

Each mixer produced nets the firm= $6

Using this all data linear system of equation will be:

$x_{1} + 2x_{2} =24 ----- (1)\\2x_{1} + 2x_{2} = 30 ----- (2)\\$

profit function:

$z= 7x_{1} +6x_{2} --- (3)$

$from (1)\\x_{1} = 0 \implies x_{2}= 12\\x_{2}= 0 \implies x_{1}= 24\\$

Coordinate points obtained from (1) are (0,12) and (24,0)

$from (2)\\x_{1}=0 \implies x_{2}=10\\x_{2}=0 \implies x_{1}=15\\$

Coordinate points obtained from (2) are (0,10) and (15,0)

plotting these on graph

points lying in feasible region are:

A(0,0)

B(0,10)

C(3,11)

D(12,0)

substituting these points in (3) to find the maximum profit:

for A (0,0)

z = 0

for B (0,10)

z = 60

for C (3,11)

z = 87

for D (12,0)

z=84

So maximum profit is $87 when 3 blenders and 11 mixers are produced.

4 0

3 years ago