Answer:
The 99% confidence interval is 
Step-by-step explanation:
From the question we are told that
The sample size is 
The the number that are parents x = 175
The proportion of parents is mathematically represented as
substituting values
The level of confidence is given as 99% which implies that the level of significance is

1%

The critical value for this level of significance is obtained from the table of critical value as

Generally the margin of error is mathematically evaluated as

substituting values


Generally the 99% confidence interval is mathematically represented as

substituting values


See the attached figure
See the attached figure.
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The first equation is
4x + 2x²(3x-5) = 4x + 6x³ - 10x² = 6x³ - 10x² + 4x
So, The degree of the function = 3 , and the number of terms = 3
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The second equation is
(-3x⁴ + 5x³ - 12 ) + ( 7x³ - x⁵ + 6 ) = -x⁵ -3x⁴ +12x³ - 6
So, The degree of the function = 5 , and the number of terms = 4
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The third equation is
(3x² - 3)( 3x² + 3) = 9x⁴ - 9
So, The degree of the function = 4 , and the number of terms = 2
We will solve this problem by unitary method which states:
"The unitary method is a technique which is used for solving a problem by finding the value of a single unit, i.e., 1, (by dividing) and then finding the necessary value by multiplying the single unit value."
Numbers of plotted plants watered by
of water in a bucket = 1 plant.
Number of plotted plants watered by the amount of water in 1 bucket = 
=
= 4 plants.
Number of plotted plants watered by the amount of water in 3 buckets = 
= 12 plants.
First, let's find the number of lunches:
14*3 = 42
To find how many lunches have ham sandwiches, we multiply the total number of sandwiches by the percentage of the ham sandwiches:
0.55 * 42
Multiply:
23.1
We can round down:
There are about 23 lunches with ham sandwiches