Answer:
sqrt(13)
All vectors here have the same magnitude because they are the same vector, just moved around.
Step-by-step explanation:
Vector v goes from(-3,-4) to (-1, -1) to find the vector you simply find the difference of each coordinate <-1 - -3, -1 - -4> = <-1+3, -1+4> = <2,3>
All vectors here are the same, just moved around, so they have the same form and magnitude, just a heads up. anyway, magnitude is the distance formula.
sqrt(2^2 + 3^2) = sqrt(13)
Okay, so here is a small lesson on rounding. When you round you MUST know the place value of each number. Ones, tens, hundreds, thousands, millions.
So, when we look at this number what do we have in the ones place --there is a 0 -- in the tens place we have a 9 and in the the thousands place we have 5. to round this number look at the tens place. if the number is greater than 5 you round 73590 to 73600, if it is 4 and lower it stays the same and the numbers behind change to zero--> like so 73500. But for this problem it would round up to 73600.
The answer is 6
Hope this helps
Answer:
41. f⁻¹(x) = -9x + 4
43. m⁻¹(x) = ∛(x-2)/4
Step-by-step explanation:
41. y = (4-x)/9
swap x and y: x = (4-y)/9
solve y: 9x = 4-y
y = -9x + 4
45. y = 4x³+2
x = 4y³+2
4y³ = x-2
y³ = (x-2)/4
y = ∛(x-2)/4
Let you do 42 and 46 by yourself
