1 pound = 16 ounces
6 ounces each pie
36 mini pies to make
36 × 6 = 216 ounces needed to make 36 mini pies
216 ÷ 16 = 13.5 pounds
if each can of pumpkin is 2 pounds,
13.5 ÷ 2 = 6.75 so that would be 7 cans of pumpkin
Answer: 2 pounds
Step-by-step explanation: There are 16 ounces in one pound. So when you divide 32 by 16, you get 2. Therefore your answer would be 2 pounds!
Answer:
Step-by-step explanation:
Let's identify what we are looking for in terms of variables. Sandwiches are s and coffee is c. Casey buys 3 sandwiches, which is represented then by 3s, and 5 cups of coffee, which is represented by 5c. Those all put together on one bill comes to 26. So Casey's equation for his purchases is 3s + 5c = 26. Eric buys 4 sandwiches, 4s, and 2 cups of coffee, 2c, and his total purchase was 23. Eric's equation for his purchases then is 4s + 2c = 23. In order to solve for c, the cost of a cup of coffee, we need to multiply both of those bolded equations by some factor to eliminate the s's. The coefficients on the s terms are 4 and 3. 4 and 3 both go into 12 evenly, so we will multiply the first bolded equation by 4 and the second one by -3 so the s terms cancel out. 4[3s + 5c = 26] means that 12s + 20c = 104. Multiplying the second bolded equation by -3: -3[4s + 2c = 23] means that -12s - 6c = -69. The s terms cancel because 12s - 12s = 0s. We are left with a system of equations that just contain one unknown now, which is c, what we are looking to solve for. 20c = 104 and -6c = -69. Adding those together by the method of elimination (which is what we've been doing all this time), 14c = 35. That means that c = 2.5 and a cup of coffee is $2.50. There you go!
It's an irrational number, so you can get as close as you need to, but
you can't write it exactly with numbers. As a decimal, it never ends.
-- The number <em>5.4175</em> is within 0.00003% of the actual value.
-- (5.4175)³ is less than 0.000084% smaller than 159 .
Answer:
Please, see the attached files.
Step-by-step explanation:
Please, see the attached files.
Thanks.