Answer:
If the line RS has been rotated 90 degrees, then VU will be perpendicular to RS and the two slopes must be opposite and reciprocal, i.e. product of the two slopes will equal -1.
As a verification, we find the locations of V and U from rotations of R & S.
(actually, the triangle had been rotated -90°, 90 ° clockwise)
Step-by-step explanation:
Slope RS, m1:
Slope VU, m2
Hence m1*m2=1*-1=-1, meaning that m1 and m2 are opposite (in sign) and are reciprocal to each other, as expected
Answer:
Side 1=21 ft, Side 2=7, Side 3=24
Step-by-step explanation:
52 = (3x) + (x) + (x+17) -> 52 = 5x + 17 -> 5x = 35 -> x = 7
Plus 7 into the equation whenever you see an x.
Answer: 195.5 or 12 7/32
Step-by-step explanation:
There is no letter tetha in the table so I use α instead. However it is not sence to final result.
The expression is:
(sinα+cosα)/(cosα*(1-cosα))
Lets divide the nominator and denominator by cosα
(sinα/cosα+cosα/cosα)/(cosα*(1-cosα)/cosα)= (tanα+1)/(1-cosα)=
=(8/15+1)/(1-cosα)= 23/(15*(1-cosα)) (1)
As known cos²α=1-sin²α (divide by cos²α both sides of equation)
cos²a/cos²α=1/cos²α-sin²α/cos²α
1=1/cos²α-tg²α
1/cos²α=1+tg²α
cos²α=1/(1+tg²α)
cosα=sqrt(1/(1+tg²α))= +-sqrt(1/(1+64/225))=+-sqrt(225/(225+64))=
=+-sqrt(225/289)=+-15/17 (2)
Substitute in (1) cosα by (2):
1st use cosα=15/17
1) 23/(15*(1-cosα)) =23/(15*(1-15/17))= 23*17/2=195.5
2-nd use cosα=-15/17
2)23/(15*(1-cosα)) =23/(15*(1+15/17))= 23*17/32=12 7/32
Answer:
11
Step-by-step explanation:
Simplify both sides of the equation.
Subtract 15 from both sides.
Divide both sides by -2.
x = 11
Answer:
x=2.32
Step-by-step explanation:
-1.32+x=1
add 1.32 to both sides
1.32 cancels itself out
so you are left with x=2.32
