Given pair of lines are x² + 4xy + y² = 0
⇒ (y/x) ² + 4 y/x + 1 = 0
⇒ y/x = -4±2√3/2 = -2±√3,
∴ The lines y = (-2 + √3) x and y = (-2 - √3) x and x - y = 4 forms an equilateral triangle
Clearly the pair of lines x² + 4xy +y² = 0 intersect at origin,
The perpendicular distance form origin to x - y = 4 is the height of the
h = 2 √ 2
∵ Area of triangle = h²/√3 = 8/√3
Answer:
it should be 3.3 repeating but maybe your teacher has it as 3.34?
Answer:
Step-by-step explanation:
The slope-intercept form of an equation of a line:
<em>m</em><em> - slope</em>
<em>b</em><em> - y-intercept</em>
The formula of a slope:
We have two points (2, -2) and (4, -1).
Substitute:
Put the value of a slope and the coordinates of the point (2, -2) to the equation of a line:
<em>subtract 1 from both sides</em>
Finally:
Answer:
b, c, and f
just divide 24/30 and youll arrive at .8! .8 is also the same as 8/10 and 80%
