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Eva8 [605]
3 years ago
9

Does this table show a proportional relationship? If so, what is the constant of proportionality?

Mathematics
1 answer:
seropon [69]3 years ago
5 0

Answer:

The answer is A: Yes 1/4 is the constant property.

This is because the x ration to y is 3 to 12. So we divide 12 by 3 to get our answer which is 4. That is equivalent to 1/4 since we divided.

I hope this helps and if it did pls give me brainliest!

Step-by-step explanation:

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4(x+6)≤−56 it says Solve the inequality.
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\tt \: 4(x + 6) \leqslant  - 56

Divide both sides of the inequality by 4

\sf \: x + 6 \leqslant  - 14

Move the constant to the right-hand side and change its sign

\bf \: x \leqslant  - 14 - 6

Calculate the difference

\rm \: x \leqslant  - 20

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Which of the following would be a good reason to place your money into a savings account? a. You can purchase stocks with a savi
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Answer: B. a savings account earns interest

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8 0
3 years ago
At the honda dealership,45% of all cars sold include a sunroof. If this sold 247 cars last week, about how many would you expect
sertanlavr [38]
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7 0
3 years ago
Chloe is painting on a stretched canvas that has an area of 108 square inches. The length of the canvas is 12 inches. The width
Stolb23 [73]

Answer: Width of canvas = 9 inches

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Explanation :

Since we have given that

Area of painting = 108 square inches

Length of canvas = 12 inches

As we know that

\text{Area of rectangle} = length\times breadth

108=12\times breadth\\\\\frac{108}{12}=breadth\\\\9=breadth

So, breadth of canvas = 9 inches .

Now, Chloe paints a 1 inch wide blue border on the canvas.

\text{So, remaining length left for painting after painting the border} = 9-1-1=9-2=7\text{ inches}

\text{ Remaining breadth left for painting after painting the border }= 12-1-1=12-2= 10\text{ inches}

\text{So , area of remaining portion }= length\times breadth \\\\ \text{ area of remaining portion }=7\times 10\\\\\text{ area of remaining portion }=70 \text{ square inches}

Hence, remaining area = 70 square inches .

6 0
3 years ago
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