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anzhelika [568]

3 years ago

10

Estimate the product of 79.623 times 4.83

1 answer:

r-ruslan [8.4K]3 years ago

4 0

It would be 384.58, or 384.57909

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Robert was able to travel 292 miles in 4 hours and uses 38 l of gasoline. if gas costs $2.09 per gallon, how much did the trip c

Butoxors [25]

cost of 1 gallon gas = $2.09

cost of 3.785 litres gas = $2.09 ( 1 gallon = 3.785 litres)

cost of 1 litre gas = 2.09/3.785

cost of 18 litres gas = 2.09/3.785 * 18 = $20.982

7 0

3 years ago

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Which equation, when solved gives the 8 the value of X?

andreev551 [17]

Answer:

C

Step-by-step explanation:

7 0

1 year ago

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State the value of the expression<br> (4.1 × 10^2)(2,4 × 10^3) over (1.5 × 10^7)

Gekata [30.6K]

$\frac{(4.1\cdot10^2)(2.4\cdot10^3)}{1.5\cdot10^7}=\frac{4.1\cdot2.4}{1.5}\cdot10^{2+3-7}=6.56\cdot10^{-2}=0.0656$

5 0

3 years ago

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What property is -2x - 2 + 5x

kompoz [17]

Answer:

3x-2

Step-by-step explanation:

-2x-2+5x=-2x+5x-2=3x-2

8 0

2 years ago

Plutonium-240 decays according to the function L where o

PIT_PIT [208]

Answer:

$\boxed{\textbf{1700 yr}}$

Step-by-step explanation:

$-\dfrac{\text{d}L}{\text{d}t} = kL\\\\\dfrac{dL}{L}=-kdt\\\\\ln L = -kt + C\\\text{At t = 0, L = L$_{0}$, so C = $\ln L_{0}$}\\\ln L = -kt + \ln L_{0}\\\ln L_{0} - \ln L = kt\\\\\ln \dfrac{L_{0}}{L} =kt$

Data:

L₀ = 24 g

L = 20 g

k = 0.000 11 yr⁻¹

Calculation:

$\ln \dfrac{24}{20} =0.000 11t\\\\\ln 1.2 = 0.000 11t\\\\0.1823 = 0.000 11t\\\\t = \dfrac{0.1823}{0.000 11} = \textbf{1700 yr}\\\\\text{It will take } \boxed{\textbf{1700 yr}}\text{ for the polonium to decay to 20 g}$

8 0

3 years ago