Explain to me how to do this please

The table represents a linear function. find the values of a,b, and c. Show your work.

viva [34]

Answer:

The values of a , b , c are ⇒ a = 1 , b = 10 , c = 9

Step-by-step explanation:

* Lets describe the meaning of the linear function

- Linear function is represented by a line graphically

- The equation of the line is y = mx + c, where m is the slope

of the line and c is the y-intercept (the point of intersection

between the line and the y-axis is (0 , c))

- m = change of y/change of x

- We can find m from any two points on the line

* Lets use m to find a, b and c

- Use the points (3 , 8) and (5 , 9) to find m

∵ m = (y2 - y1)/(x2 - x1)

∴ m = (9 - 8)/(5 - 3) = 1/2

- Find a by using points (a , 7) and (3 , 8) ⇒ (or (5 , 9))

∵ m = (8 - 7)/(3 - a) = 1/2

∴ 1/(3 - a) = 1/2 ⇒ by using cross multiplication

∴ 3 - a = 2 ⇒ subtract 3 from both sides

∴ -a = -1 ⇒ × -1 both sides

∴ a = 1

- Find b by using points (5 , 9) and (7 , b) ⇒ (or (3 , 8))

∵ m = (b - 9)/(7 - 5) = (b - 9)/2

∴ (b - 9)/2 = 1/2 ⇒ by using cross multiplication

∴ 2(b - 9) = 2 ⇒ open the bracket

∴ 2b - 18 = 2 ⇒ add 18 to both sides

∴ 2b = 20 ⇒ ÷ 2

∴ b = 10

- Find b by using points (5 , 9) and (c , 11) ⇒ (or (3 , 8))

∵ m = (11 - 9)/(c - 5) = 2/(c - 5)

∴ 2/(c - 5) = 1/2 ⇒ by using cross multiplication

∴ c - 5 = 4 ⇒ add 5 to both sides

∴ c = 9

* The values of a , b , c are ⇒ a = 1 , b = 10 , c = 9

6 0

3 years ago

If you set aside $9000 at the end of each year for the next 22 years in a Roth IRA, how much will you have at your retirement 22

madam [21]

Answer:

$501,049.37

Step-by-step explanation:

For computing the amount after 22 years we need to applied the future value which is shown in the attachment below:

Given that

PMT = $9,000

NPER = 22 years

Annual rate = 0.078

Quarterly= 0.078 ÷ 4 = 0.0195

Effective annual rate = (1.0195^4) - 1 = 0.0803113041

Now applied the formula which is given below

= -FV(RATE;NPER;PMT;PV)

After applying the above formula, the future value is $501,049.37

7 0

3 years ago

For each store, what is the ratio of the number of cans to the price?

leva [86]

Well $ 4.50 for the 24 pack.$2.50 for the 4 for 10,12 pack and the last is $3.00.

7 0

3 years ago

a file that is 278 megabytes is being downloaded. If downloaded is 14.1% complete, how many megabytes been downloaded? To round

Gekata [30.6K]

14.1% of 278 is 39.2. So 39.2 megabytes have been downloaded.

4 0

3 years ago

Read 2 more answers

an inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a

viktelen [127]

Answer:

the rate of change of the water depth when the water depth is 10 ft is; $\mathbf{\dfrac{dh}{dt} = \dfrac{-25}{100 \pi} \ \ ft/s}$

Step-by-step explanation:

Given that:

the inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec.

We are meant to find the rate of change of the water depth when the water depth is 10 ft.

The diagrammatic expression below clearly interprets the question.

From the image below, assuming h = the depth of the tank at a time t and r = radius of the cone shaped at a time t

Then the similar triangles ΔOCD and ΔOAB is as follows:

$\dfrac{h}{r}= \dfrac{20}{8}$ ( similar triangle property)

$\dfrac{h}{r}= \dfrac{5}{2}$

$\dfrac{h}{r}= 2.5$

h = 2.5r

$r = \dfrac{h}{2.5}$

The volume of the water in the tank is represented by the equation:

$V = \dfrac{1}{3} \pi r^2 h$

$V = \dfrac{1}{3} \pi (\dfrac{h^2}{6.25}) h$

$V = \dfrac{1}{18.75} \pi \ h^3$

The rate of change of the water depth is :

$\dfrac{dv}{dt}= \dfrac{\pi r^2}{6.25}\ \dfrac{dh}{dt}$

Since the water is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec

Then,

$\dfrac{dv}{dt}= - 4 \ ft^3/sec$

Therefore,

$-4 = \dfrac{\pi r^2}{6.25}\ \dfrac{dh}{dt}$

the rate of change of the water at depth h = 10 ft is:

$-4 = \dfrac{ 100 \ \pi }{6.25}\ \dfrac{dh}{dt}$

$100 \pi \dfrac{dh}{dt} = -4 \times 6.25$

$100 \pi \dfrac{dh}{dt} = -25$

$\dfrac{dh}{dt} = \dfrac{-25}{100 \pi}$

Thus, the rate of change of the water depth when the water depth is 10 ft is; $\mathtt{\dfrac{dh}{dt} = \dfrac{-25}{100 \pi} \ \ ft/s}$

4 0

3 years ago