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Ad libitum [116K]
3 years ago
10

What is f(x) = 2x2 + 28x – 5 written in vertex form? f(x) = 2(x + 7)2 – 19 f(x) = 2(x + 7)2 – 103 f(x) = 2(x + 14)2 – 14 f(x) =

2(x + 14)2 – 98
Mathematics
2 answers:
lesantik [10]3 years ago
7 0

Answer: B. f(x) = 2(x + 7)² - 103

<u>Step-by-step explanation:</u>

y=2x^2+28x-5\\\\\\y+5=2x^2+28x\\\\\\y+5=2(x^2+14x+\underline{\quad}\ )\\.\qquad \qquad \qquad \ \ \downarrow\\.\qquad \qquad \qquad \bigg(\dfrac{14}{2}\bigg)^2=7^2 \\\\\\y + 5 + 2(7)^2=2(x^2+14x+\underline{7^2} )\\\\\\y + 5 + 98 = 2(x + 7)^2\\\\\\y+103=2(x+7)^2\\\\\\y=2(x+7)^2-103

padilas [110]3 years ago
6 0

Answer:

f(x)=2(x+7)^2-103

Step-by-step explanation:

f(x)=2x^{2} +28x-5\\=2(x^2+14x)-5\\=2(x^2+2(7)x+7^2-7^2)-5\\=2(x+7)^2-2(49)-5\\=2(x+7)^2-103

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Select the correct answer.
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Answer: C: Euros

Step-by-step explanation: We know it is in euros because Germany has not branched off of the EU (European Union), it still uses euros, the currency of all of the countries in the EU.

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WHY IS THIS GETTING DELETED?? I NEED HELP
aliina [53]

If this exact question is repeatedly deleted, it's probably because of the ambiguity of the given equation. I see two likely interpretations, for instance:

\dfrac{(5\times5)^k}{5^{-8}} = 5^3

or

\dfrac{5\times 5^k}{5^{-8}} = 5^3

If the first one is what you intended, then

\dfrac{(5\times5)^k}{5^{-8}} = \dfrac{(5^2)^k}{5^{-8}} = \dfrac{5^{2k}}{5^{-8}} = 5^{2k-(-8)} = 5^{2k+8} = 5^3

and it follows that

2<em>k</em> + 8 = 3   ==>   2<em>k</em> = -5   ==>   <em>k</em> = -5/2

If you meant the second one, then

\dfrac{5\times 5^k}{5^{-8}} = \dfrac{5^1\times5^k}{5^{-8}} = \dfrac{5^{k+1}}{5^{-8}} = 5^{k+1-(-8)} = 5^{k+9} = 5^3

which would give

<em>k</em> + 9 = 3   ==>   <em>k</em> = -6

And for all I know, you might have meant some other alternative... When you can, you should include a picture of your problem.

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2 years ago
Whole numbers are _____ integers.<br><br> A.always<br> B.sometimes<br> C.never
gulaghasi [49]
The answer to the question is always.
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A lawyer charges a $75 consultation fee and then $120 per hour thereafter.
Ainat [17]

Answer:

(a) The dependant veriable is the $120 per hour and the independant veriable is the $75 consultaion fee.
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\frac{C}{T} \frac{75}{0} \frac{195}{1} \frac{315}{2} \frac{435}{3} \frac{555}{4}, where C = cost and T = time.
(c) The relationship between C and T is linear, beacause with the more hours you take the cost increases.
(d) Yes, it is sensible because the points would be in line due to the steady increase of the hourly rate.

(e) For every hour spent the cost increases 120 dollars.
(f) The fixed cost is 75 dollars for consultation and the veriable cost is 120 per hour.

3 0
2 years ago
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