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Ivan
3 years ago
12

Solve for v. (v-1)^2 = 2v^2 -5v -17 If can be more than one solution or no solution

Mathematics
1 answer:
GuDViN [60]3 years ago
3 0
             (v - 1)² = 2v² - 5v - 17
     (v - 2)(v - 2) = 2v² - 5v - 17
v² - 2v - 2v + 4 = 2v² - 5v - 17
       v² - 4v + 4 = 2v² - 5v - 17
    <u>- v²                  - v²               </u>
            -4v + 4 = v² - 5v - 17
          <u>+ 5v              + 5v        </u>
               v + 4 = v² - 17
               <u>   + 17     + 17</u>
             v + 21 = v²
                     0 = v² + v + 21
      v² + v + 21 = 0
                     v = <u>-(1) +/- √((1)² - 4(1)(21))</u>
                                           2(1)
                     v = <u>-1 +/- √(1 - 84)</u>
                                      2
                     v = <u>-1 +/- √(-83)
</u>                                    2<u>
</u>                     v = <u>-1 +/- 9.11i
</u>                                    2<u>
</u>                     v = -1 <u>+</u> 4.555i<u>
</u>                     v = -1 + 4.555i        v = -1 - 4.555i

There is more than one solution.

<u />
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Answer:

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