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3 years ago

What’s the equation for the two points (19, 3) and (20,3)

Mathematics

1 answer:

Orlov [11]3 years ago

7 0

Answer:

Equation of line passing through point A = ( 19 , 3 ) , and point B = ( 20 , 3 ) is

y−3=0

Equation of line passing through point A = ( 19 , 3 ) , and point B = ( 29 , 3 ) is

y=0x+3

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Pls help i need help ASappp

Harrizon [31]

A=πr2=π·92≈254.469
your answer is 254.469

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2 years ago

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What is 2,400 milliliters converted into liters

BARSIC [14]

Answer:

2.4 liters

Step-by-step explanation:

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3 years ago

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Why do I measure capacity

earnstyle [38]

To find the maximum for something pertaining to a liquid or etc.

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2 years ago

A competitive knitter is knitting a circular place mat. The radius of the mat is given by the formula

Ilia_Sergeevich [38]

Answer: A. $A'(t)=\frac{4356\pi}{(t+11)^{3}}-\frac{527076\pi}{(t+11)^{5}}$

B. A'(5) = 1.76 cm/s

Step-by-step explanation: Rate of change measures the slope of a curve at a certain instant, therefore, rate is the derivative.

A. Area of a circle is given by

$A=\pi.r^{2}$

So to find the rate of the area:

$\frac{dA}{dt}=\frac{dA}{dr}.\frac{dr}{dt}$

$\frac{dA}{dr} =2.\pi.r$

Using $r(t)=3-\frac{363}{(t+11)^{2}}$

$\frac{dr}{dt}=\frac{726}{(t+11)^{3}}$

Then

$\frac{dA}{dt}=2.\pi.r.[\frac{726}{(t+11)^{3}}]$

$\frac{dA}{dt}=2.\pi.[3-\frac{363}{(t+11)^{2}}].\frac{726}{(t+11)^{3}}$

Multipying and simplifying:

$\frac{dA}{dt}=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}$

The rate at which the area is increasing is given by expression $A'(t)=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}$ .

B. At t = 5, rate is:

$A'(5)=\frac{4356\pi}{(5+11)^{3}} -\frac{527076\pi}{(5+11)^{5}}$

$A'(5)=\frac{4356\pi}{4096} -\frac{527076\pi}{1048576}$

$A'(5)=\frac{2408693760\pi}{4294967296}$

$A'(5)=1.76268$

At 5 seconds, the area is expanded at a rate of 1.76 cm/s.

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2 years ago

Find p(4) when p=.80

deff fn [24]

Answer:

3.2

Step-by-step explanation:

0.8(4) = 3.2

3 0

2 years ago