Answer:
Graph B
Step-by-step explanation:
y = (x - 3)(x - 3)
The x intercepts are at 3
Since both intercepts are at 3, the vertex is at 3
We know it is an upwards facing parabola since it is quadratic and the constant out front is positive
Step-by-step explanation:
We have been given that AE=BE and
.
We can see that angle CEA is vertical angle of angle DEB, therefore,
as vertical angles are congruent.
We can see in triangles CEA and DEF that two angles and included sides are congruent.


or
Therefore,
by ASA postulate.
Since corresponding parts of congruent triangles are congruent, therefore CE must be congruent to DE.
Answer:
d. parabola, 0°
Step-by-step explanation:
y² + 8x - 0
y² = -8x
Where x = cos t , y = sin t
Sin² t = -8 Cos t
1 - Cos² t = -8 Cos t
- Cos² t + 8 Cos t + 1 = 0
t = 2лπ ± (3 + √10) , л∈Z
Angle of rotation
Answer:
Only 60 is an identified outlier
Step-by-step explanation:
Given
<u>Age group: 40 to 50</u>


<u>Conditions for outlier</u>


<em>See attachment for complete question</em>
<u>Required</u>
Which of 60, 62 and 84 is an outlier of age grout 40 to 50 years
First, calculate the IQR of group 40 to 50.
This is calculated as:

Where:
and 
So:


<em>Next, is to test the outlier conditions on each value (i.e. 60, 62 and 84)</em>
<u></u>
<u>Testing 60</u>
<u>Condition 1</u>



--- False
<u>Condition 2</u>



--- True
<em>Because one of the conditions is true, then 60 is an outlier of group 40 - 50 years</em>
<em></em>
<u>Testing 62</u>
<u>Condition 1</u>



--- False
<u>Condition 2</u>



--- False
<em>Because both conditions are false, then 62 is not an outlier of group 40 - 50 years</em>
<em></em>
<u>Testing 84</u>
<u>Condition 1</u>



--- False
<u>Condition 2</u>



--- False
<em>Because both conditions are false, then 84 is not an outlier of group 40 - 50 years</em>