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sweet [91]
4 years ago
13

How do you change -3 in x^-3 to be positive?

Mathematics
2 answers:
Komok [63]4 years ago
7 0

Answer:

Take the reciprocal. 1/x^3

Step-by-step explanation:

When you take the reciprocal of a number or a variable, the exponent changes sign.

Vladimir79 [104]4 years ago
6 0

Answer:

x^-3=1/x^3

This is how we do it.

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How has people's actions helped protect endangered animals
viva [34]
   I think we have found them and cared for them I don't think it's right b/c I guessed.
7 0
3 years ago
Expand. (1-4m)(m^2-3m+8) your answer should be a polynomial in standard form.
sergiy2304 [10]

Answer:

 13m²−35m+8−4m³

Step-by-step explanation:

Expand (1 − 4m)(m² − 3m + 8) by multiplying each term in the first expression by each term in the second expression.

1m² + 1 (−3m) + 1 ⋅ 8 − 4m ⋅ m² − 4m (−3m) − 4m ⋅ 8

Simplify terms.

13m²−35m+8−4m³

8 0
2 years ago
An urn contains 8 red chips, 10 green chips, and 2 white chips. A chip is drawn and replaced, and then a second chip is drawn.
Harlamova29_29 [7]

Answer:

(A) 0.04

(B) 0.25

(C) 0.40

Step-by-step explanation:

Let R = drawing a red chips, G = drawing green chips and W = drawing white chips.

Given:

R = 8, G = 10 and W = 2.

Total number of chips = 8 + 10 + 2 = 20

P(R) = \frac{8}{20}=\frac{2}{5}\\P(G)=  \frac{10}{20}=\frac{1}{2}\\P(W)=  \frac{2}{20}=\frac{1}{10}

As the chips are replaced after drawing the probability of selecting the second chip is independent of the probability of selecting the first chip.

(A)

Compute the probability of selecting a white chip on the first and a red on the second as follows:

P(1^{st}\ white\ chip, 2^{nd}\ red\ chip)=P(W)\times P(R)\\=\frac{1}{10}\times \frac{2}{5}\\ =\frac{1}{25} \\=0.04

Thus, the probability of selecting a white chip on the first and a red on the second is 0.04.

(B)

Compute the probability of selecting 2 green chips:

P(2\ Green\ chips)=P(G)\times P(G)\\=\frac{1}{2} \times\frac{1}{2}\\ =\frac{1}{4}\\ =0.25

Thus, the probability of selecting 2 green chips is 0.25.

(C)

Compute the conditional probability of selecting a red chip given the first chip drawn was white as follows:

P(2^{nd}\ red\ chip|1^{st}\ white\ chip)=\frac{P(2^{nd}\ red\ chip\ \cap 1^{st}\ white\ chip)}{P (1^{st}\ white\ chip)} \\=\frac{P(2^{nd}\ red\ chip)P(1^{st}\ white\ chip)}{P (1^{st}\ white\ chip)} \\= P(R)\\=\frac{2}{5}\\=0.40

Thus, the probability of selecting a red chip given the first chip drawn was white is 0.40.

6 0
3 years ago
Robin Hartman earns 681 per week plus 2% of sales over 6,500. Robins sales are 13,300. How much does robin earn?
barxatty [35]

Answer:

Robin earns 635 + 0.02*(12350-6500) dollars.

Step-by-step explanation:

Just know please mark branliest

3 0
2 years ago
Identify proportional relationships from tables
Sveta_85 [38]

Answer:

?

Step-by-step explanation:

4 0
4 years ago
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