Answer:
Step-by-step explanation:
the transverse axis is horizontal.
so its a horizontal hyperbola
Center is the origin so center is (0,0)
Equation of horizontal hyperbola is
Given a= 55000 and c= 81000
c^2 = a^2 + b^2
81000^2 = 55000^2 + b^2
subtract 55000^2 on both sides
b = sqrt(81000^2 - 55000^2)= 59464.27
now plug in the values
Answer:
2/7
Step-by-step explanation:
There are 22 (12 + 10) total students in the class. That means that the chance of the first student picked being a girl is 12/22.
Now, we must calculate the chance of the next student to be picked <em>also </em>being a girl - however, there is a trap here! Remember that since a girl has been picked, the total student pool has decreased to 21 and and the total number of girls has decreased to 11. This means the new chance of girl being picked is 11/21.
To find the probability of both these events happening in conjunction, these fractions must be multiplied. 12/22 * 11/21 = 132/462, which simplifies to 2/7.
Answer:
b
Step-by-step explanation:
80 = -1(80), -2(40), -4(20), -5(4),
Total answers include: -81, 79, -42, 16, -9, and 1.
None of them add up to 6!
Are you doing polynomial equations?
If so, you can solve it the hard way.
x^2 + 6x -80 = 0
(x^2 + 6x + 9) - 80 = 9
(x+3)^2 = 89
(x+3) = 9.43
x = 6.43
If you're not doing those then I'm afraid your question has no answer.
Hope that helps!
2 2/5=12:5
5 1/5= 26:5
12:26:5
I think.
