Answer:
C. 57
Step-by-step explanation:
all triangles add up to 180. the tick marks show that ∠D and ∠ E are congruent so you do this and solve for x:
(4x + 1) + (4x + 1) + (5x - 4) = 180
13x - 2 = 180
13x = 182
x = 182/13
x = 14
4(14) + 1 = 57
I’m most likely sure it’s 0
=
−
9
Answer:

Step-by-step explanation:
when adding logs, apply the log rule: 
∴ 
when subtracting logs, apply the log rule: 

Answer:

Step-by-step explanation:
A polynomial is given to us . We need to find the value of c so that it is divisible by (x-3 ) .The given polynomial to us is ,
And the factor is ,

Now , according to factor theorem , p(x) will be divisible by g(x) if p(-3) = 0

<h3>
<u>Hence </u><u>the </u><u>value </u><u>of </u><u>c </u><u>is </u><u>(</u><u>-</u><u>1</u><u>4</u><u>)</u><u>/</u><u>3</u><u> </u><u>.</u></h3>