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skelet666 [1.2K]
3 years ago
5

2x+5(x+1) = -8; Can someone help me solve this problem step by step please?

Mathematics
2 answers:
Eva8 [605]3 years ago
5 0

Answer:

x = -13/7

Step-by-step explanation:

2x+5(x+1) = -8

2x+5x+5 = -8

7x+5 = -8

7x = -8-5

7x = -13

x = -13/7

mariarad [96]3 years ago
4 0

Answer:

-13/7

Step-by-step explanation:

2x+5(x+1)=-8

2x+5x+5=-8

7x+5=-8

7x=-8-5

7x=-13

7x/7=-13/7

x=-13/7

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Please help<br> Value of x<br> and what are angles m thank you!
Usimov [2.4K]

To find the value of x, you want to use the vertical angles theorem.

The vertical angles theorem says that all vertical angles (which is what TRY and QRW are) are congruent to each other. Knowing this you can make an equation where the angles are equal to each other to find the value of x.

TRY = QRW, so:

(x+16) = (4x-5)

1. Add 5 to both sides.

(x+21) = (4x)

2. You can get rid of the parentheses.

x+21 = 4x

3. Subtract x from both sides.

21 = 3x

4. Divide both sides by 3, isolating x.

7 = x

5. Flip this equation around, so:

x = 7

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To find the measure of TRY then plug x into the expression for TRY, which is (x+16).

TRY => ((7)+16) = 23

Since TRY is 23, the vertical angles theorem says that QRW is also 23. Add these measures up.

23+23 = 46

A line's measure is 180 degrees, so two lines would add up to 360 degrees. Subtract 46 from 360 to find the remaining degrees.

360-46 = 314

TRQ and YRW must be congruent to each other so that means you can divide 314 by 2.

314/2 = 157

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Answers are:

TRY = 23

TRQ = 157

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3 years ago
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Read 2 more answers
Find the area of the curve y= f(x) = x between x = 5 and x = 10
Tems11 [23]

Answer:

the area of the curve y= f(x) = x between x = 5 and x = 10

A=\frac{75}{2}

Step-by-step explanation:

  • Finding the area of the curve  y = f(x) = x between x = 5 and x = 10

Using the Area formula

A=\int _a^b\:f\left(x\right)dx

As the area of curve lies between x = 5 and x = 10

so

  • a = 5, b = 10

so the integral expression becomes

A=\int _5^{10}xdx

\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1

A=\left[\frac{x^{1+1}}{1+1}\right]^{10}_5

    =\left[\frac{x^2}{2}\right]^{10}_5

     =\frac{1}{2}\left[10^2-5^2\right]

     =\frac{1}{2}\cdot \:75

     =\frac{75}{2}

Therefore, area of the curve y= f(x) = x between x = 5 and x = 10

A=\frac{75}{2}

4 0
3 years ago
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